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3 years ago

Complete the paragraph proof

Mathematics

1 answer:

Mila [183]3 years ago

5 0

<span>By the definition of supplementary angles,
M<1+M<2=180
M<2+M<3=180
M<1+M<2=M<2+M<3=180
Subtract M<2 from each side, You get M<1=M<3 or <1 is congruent to <3
</span>

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Whats an equation slop 0.5, passes through(6,4)

4vir4ik [10]

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3 years ago

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Dmitriy789 [7]

Answer:

=1/15

Step-by-step explanation:

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3 years ago

Read 2 more answers

Complete the table for the following function<br> y=(1/3)^x

Bumek [7]

x=-3 then y= 27

x= -2 then y= 9

x=2 then y: $y=\frac{1}{9}$

x=3 then y: $y=\frac{1}{27}$

The graph of the function decreases from left to right.

Option C is correct.

Step-by-step explanation:

We are given the function: $y=(\frac{1}{3})^x$

and we need to fill the table

if x = -3 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^-3$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{\frac{1}{27}}\\y=27$

if x = -2 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^-2$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{\frac{1}{9}}\\y=9$

if x = 2 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^2$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{9}$

if x = 3 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^3$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{27}$

So, x=-3 then y= 27

x= -2 then y= 9

x=2 then y: $y=\frac{1}{9}$

x=3 then y: $y=\frac{1}{27}$

Graph of the function is shown in figure attached.

The graph of the function decreases from left to right.

Option C is correct.

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

7 0

4 years ago

If x varies directly with y and y = -15 when x = 3, what is the value of y when x = 2?

Aloiza [94]

Answer:

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Step-by-step explanation:

if we cross multiply

3 0

3 years ago

Point A is at (-2,4) and point C is at (4,7). Find the coordinates of point B on AC such that the ratio of a B to a C is 1:3

Diano4ka-milaya [45]

Answer:

$[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]$

$[x=\frac{4-6}{4}, y=\frac{7+12}{4}]$

$[x=\frac{-2}{4}, y=\frac{19}{4}]$

$[x=-0.5, y=4.75]$

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

Step-by-step explanation:

We have been given that point a is at (-2,4) and point c is at (4,7) .

We are asked to find the coordinates of point b on segment ac such that the ratio is 1:3.

We will use section formula to solve our given problem.

When point P divides a segment internally in the ratio m:n, the coordinates of point P would be:

$[x=\frac{mx_2+nx_1}{m+n}, y=\frac{my_2+ny_1}{m+n}]$

$\texttt{Let point} (-2,4)=(x_1,y_1) \texttt {and point} (4,7)=(x_2,y_2).$

$[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]$

$[x=\frac{4-6}{4}, y=\frac{7+12}{4}]$

$[x=\frac{-2}{4}, y=\frac{19}{4}]$

$[x=-0.5, y=4.75]$

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

5 0

3 years ago