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3 years ago

7

A.aBoC

le=" \times + 6 \times + 19" alt=" \times + 6 \times + 19" align="absmiddle" class="latex-formula">

1 answer:

adoni [48]3 years ago

8 0

Answer:

?

Step-by-step explanation:

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PLZ HELP! ALL YOU NEED TO KNOW IS IN THE PICTURE!

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

A college student is taking two courses. The probability she passes the first course is 0.67. The probability she passes the sec

andrezito [222]

Answer:

0.58 = 58% probability she passes both courses

Step-by-step explanation:

We can solve this question treating the probabilities as a Venn set.

I am going to say that:

Event A: She passes the first course.

Event B: She passes the second course.

The probability she passes the first course is 0.67.

This means that $P(A) = 0.67$

The probability she passes the second course is 0.7.

This means that $P(B) = 0.7$

The probability she passes at least one of the courses is 0.79.

This means that $P(A \cup B) = 0.79$

a. What is the probability she passes both courses

This is $P(A \cap B)$ .

We use the following relation:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.67 + 0.7 - 0.79 = 0.58$

0.58 = 58% probability she passes both courses

5 0

3 years ago