Answer:
![3 |2x - 3| = 1](https://tex.z-dn.net/?f=3%20%7C2x%20-%203%7C%20%20%3D%201)
![3 |2x - 3| = 1 \\ 6x - 9 = 1 \\ 6x = 10 \\ x = \frac{10}{6} = \frac{5}{3}](https://tex.z-dn.net/?f=3%20%7C2x%20-%203%7C%20%20%3D%201%20%5C%5C%206x%20-%209%20%3D%201%20%5C%5C%206x%20%3D%2010%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B10%7D%7B6%7D%20%20%3D%20%5Cfrac%7B5%7D%7B3%7D%20)
![3 |2x - 3| = - 1 \\ 6x - 9 = - 1 \\ 6x = 8 \\ x = \frac{4}{3}](https://tex.z-dn.net/?f=3%20%7C2x%20-%203%7C%20%20%3D%20%20-%201%20%5C%5C%206x%20-%209%20%3D%20%20-%201%20%5C%5C%206x%20%3D%208%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20)
![x = \frac{5}{3} x = \frac{4}{3}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B5%7D%7B3%7D%20x%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20)
I am sorry but I am not sure of this :(
Answer:
GQ=25 units
Step-by-step explanation:
we know that
Point Q is the midpoint of GH
so
GH=GQ+QH and GQ=QH
GH=2GQ -------> equation A
we have
GH=5x-5
GQ=2x+3
substitute in the equation A and solve for x
5x-5=2(2x+3)
5x-5=4x+6
5x-4x=6+5
x=11
Find the length of GQ
GQ=2x+3
substitute the value of x
GQ=2(11)+3
GQ=25 units
Answer:
hope this helps you look it once.
X=12
Hope this helps
10x-20+6x+8=180º