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ololo11 [35]
3 years ago
13

Does the mass of an object make it need more force to move, and to stop?

Physics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

Yea

Explanation:

Let's compare a brick to a small table, does it take more force and strength to push a car or a small table? A car, because it's heavier and has more mass.

mel-nik [20]3 years ago
5 0

Answer:

Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects. Example: Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop.

Explanation:

☝️

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Will give brainlist and many points.
romanna [79]

Answer:

They create enormous amounts of sound energy, much like explosion. When an aircraft passes through air, it creates a series of pressure waves just like the waves created by the boat. As the speed of aircraft increases these waves are forced to compress.

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4 years ago
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Paladinen [302]

Answer:

(•_•)

Explanation:

7 0
3 years ago
Along the remote Racetrack Playa in Death valley, California,stones sometimes gouge out prominent trails in the desert floor, as
MArishka [77]

Answer:

Explanation:

given ;

  • coefficient of kinetic friction = 0.80
  • mass m = 26kg
  • considering the force acting in horizontal direction and from newton's 2nd law of motion;
  • for vertical motion = Fn - mg = 0
  • for horizontal motion = F = ma + miu mg = m( a + miu.g)
  • but a = 0
  • therefore, F = miu mg where g = 9.81m/s^2
  • plugging the values into the equation;
  • F = 0.80 x 9.81 x 26

Horizontal force = 204.05N

3 0
3 years ago
If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet
Shtirlitz [24]

The average distance between the planet and the star is:

R=9.36*10^11 m

Orbital velocity  v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

As was already said, Earth is located roughly 150 million kilometres (93 million miles) from the Sun on average. It is 1 AU. Mars is on our fictitious football field's three-yard line. On average, the distance between the Sun and the red planet is around 142 million miles (228 million kilometres).

Learn more about average distance:

brainly.com/question/18366547

#SPJ4

The complete question is ''If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 10^30 kg, what is the average distance between the planet and the star? 1.43 × 10^9 m 9.36 × 10^11 m 5.42 × 10^13 m 9.06 × 10^17 m''.

4 0
1 year ago
A 50 kg aardvark runs with a speed of 6 m/s. what is the kinetic energy of the aardvark
jeyben [28]

Answer:

900 J

Explanation:

0.5 x 50= 25 x 6^2= 900 J

5 0
4 years ago
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