Question

A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 23 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 740 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 370 N. What is the speed of the rider at the top of the loop?

Answer 1

Answer:

$v = 18.4 m/s$

Explanation:

When it reached to the top of the path the normal force is given as

$F_n = 370 N$

initially the reading of the sensor will give the amount of the weight of the object

$W = mg = 740 N$

$m = 75.4 kg$

now at the top position of the path we will have

$F_n + mg = \frac{mv^2}{R}$

$370 + 740 = \frac{(75.4)v^2}{23}$

$1110 = 3.28 v^2$

$v = 18.4 m/s$