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frozen [14]
3 years ago
7

In a certain region of space, the electric potential is V(x,y,z)=Axy−Bx^2+Cy, where A, B, and C are positive constants. (a) Calc

ulate the x-, y-, and z-components of the electric field. (Use any variable or symbol stated above as necessary.) x-component Ex, y-component Ey, z-component Ez. At what point electric field equal to zero.
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

E = (Ay-2Bx) i ^ + (Ax + C) j ^ + 0 k ^  and (-C / A i ^ + 2BC / A2 j ^)

Explanation:

The electric field the electric potential are related through the least gradient

           E = -ΔV = - dV / dx i^

Let's perform the calculations

        E = dB / dx i ^ + dV / d and j ^ + dV / dz k ^

        dv / dx = A and - B 2x

        dv / dy = Ax + C

        dv / dz = 0

        E = (Ay-2Bx) i ^ + (Ax + C) j ^ + 0 k ^

Where is E = 0

            Ex = 0

            Ay -2Bx = 0

            y = 2B / A X

            Ey = 0

            Ax + C =

            x = -C / A

           Ez = 0

For the total electric field to be steel the two components must be zero simultaneously

           y = 2B / A (-C / A)

          y = 2B C / A2

The coordinates of the point are (-C / A i ^ + 2BC / A2 j ^)

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2 years ago
What (in N/C) is the electric field 3.00 m from the center of the terminal of a Van de Graaff with an 8.00 mC charge, noting tha
mixer [17]

To solve this problem we will apply the concept related to the electric field defined from the laws of Coulomb. For this purpose we will remember that the electric field is equivalent to the product of the Coulomb constant due to the change of the charge over the squared distance, mathematically this is

E = \frac{kq}{r^2}

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