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Lana71 [14]
2 years ago
12

The Captain has probability 2/3 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with

probability 1/3
Mathematics
2 answers:
finlep [7]2 years ago
8 0

Answer:

What we have to do bro

Step-by-step explanation:

please mark me as brainlest

KonstantinChe [14]2 years ago
6 0

Answer:

PLS POST YOUR FULL QUESTION

THANKYOU

You might be interested in
What is 16/48 equivalent to?
liberstina [14]
\frac{16}{48}=\\\\\frac{16:2}{48:2}=\boxed{\frac{8}{24}}\\\\\frac{8:2}{24:2}=\boxed{\frac{4}{12}}\\\\\frac{4:2}{12:2}=\boxed{\frac{2}{6}}\\\\\frac{2:2}{6:2}=\boxed{\frac{1}{3}}\\\\\frac{1\cdot10}{3\cdot10}=\boxed{\frac{10}{30}}\\\vdots
6 0
3 years ago
Step 2: Radii OK and NL are perpendicular to OM because of the radius-tangent theorem. By definition of perpendicular, angles KO
solong [7]

Answer:

Angle Angle Angle (AAA) property

Step-by-step explanation:

A right angled triangle is a triangle that has one of its angles to equal 90^{0}. It could be in the form of an isosceles triangle or an acute angled triangle.

The given question compares the congruence properties of two triangles, KOM and LNM.

Thus,

<KOM = <LNM (right angle theorem)

<LMN = <KMO (common angles to both triangles)

⇒ <OKM = <NLM (property of a triangle i.e sum of angle in a triangle is 180^{0})

ΔKOM = ΔLNM (congruence property)

Therefore, by angle angle angle (AAA) congruence property, the two triangles are similar.

7 0
3 years ago
(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
Find the area of the trapezoid
daser333 [38]

Answer:

52√3 ft^2

Step-by-step explanation:

The area of a trapezoid is the average of the bases times the height

We have enough information to find these parts.

The average of the bases is 11+15 /2 =13

The height is 4√3

So the answer is 13 * 4√3 = 52√3

Please vote me for brainliest i really need it, i hope i helped you. :)

4 0
3 years ago
Find the roots of the following equations.<br> a) 4x+9=34<br> b) (x-4)(x+2)=0<br> c) 2x^2-6x+4=0
Masteriza [31]
A. 4x + 9 = 34
    <u>      - 9   - 9</u>
          <u>4x</u> = <u>25</u>
           4      4
            x = 6.25

B. (x - 4)(x + 2) = 0
    x - 4 = 0    U    x + 2 = 0
    <u>  + 4 + 4</u>          <u>    - 2  - 2</u>
         x = 4                 x = -2

C.          2x² - 6x + 4 = 0
    2(x²) - 2(3x) + 2(2) = 0
            <u>2(x² - 3x + 2)</u> = <u>0</u>
                      2             2
                x² - 3x + 2 = 0
                x = <u>-(-3) +/- √((-3)² - 4(1)(2))</u>
                                      2(1)
                x = <u>3 +/- √(9 - 8)</u>
                               2
                x = <u>3 +/- √(1)
</u>                            2<u>
</u>                x =<u> 3 +/- 1
</u>                          2
                x = <u>3 + 1</u>    U    x = <u>3 - 1</u>
                         2                      2
                x = <u>4</u>                 x = <u>2</u>
                      2                       2
                x = 2                 x = 1
<u />
7 0
3 years ago
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