Answer: 13.5 Okay! Here's the method count the legs of the right triangle
The formula we'll use will be
A^2 + B^2 = C^2
In this case we're counting by twos
The base is 11 so we times it by itself =110
The leg is 8.5 so we going to times itself to make 72.25 add those together so 110+ 72.25 = 182.25 then we \|-----
182.25
Then you have got ur answer of 13.5
Step-by-step explanation:
Answer: 1
Step-by-step explanation:
3x + 8x-8= 3
11x-8=3
Then you move the 8 to the other side and change it to a positive.
11x= 11
11x/11 = 11/11
Answer is 1
Is this what you mean this is what i understood.
X-4=10;4x+1=57
First equation solve for x.
X-4=10
Add 4 both sides
X=10+4
X=14
Second equation substitute your x answer into second equation to make both sides equal.
4x+1=57
4(14)+1=57
56+1=57
57=57
Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Answer:
3
Step-by-step explanation:
I think its 3 because if its 6 then you divide. it by 2
