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4 years ago

Help me on this one too

Chemistry

2 answers:

Mnenie [13.5K]4 years ago

6 0

Pancreas and i’m not sure of the last one because some of the answers are blocked out

nlexa [21]4 years ago

3 0

7 is the pancreas and 8 is i can’t see the other choices but for diabetes the glucose levels will be a lot higher

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160

IrinaK [193]

It’s 140 and it’s also 160

7 0

3 years ago

Find if the example is correct or not and explain using CER please. Will give 5/5

ELEN [110]

The Lewis structure the student drew is incorrect. The total number of electrons in bonds and lone pairs is equal to the total number of valence electrons available, then a valid Lewis structure is produced.

The correct structure is the following:

The structure that was drawn by the student was incorrect because the total number of electrons around Oxygen were incorrect, there were 6 instead of 8, which was against the octet rule. The correct structure should have 8 electrons around each atom.

5 0

1 year ago

How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4?

True [87]

Answer:

The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)

Explanation:

From the ionization of H₂SO₄, we have

H₂SO₄ → 2H⁺ + SO₄²⁻

Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).

That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.

4 0

4 years ago

A solution of acetic acid has a pH of 3.45. What is the concentration of acetic acid in this solution? Ka for CH3COOH is 1.8×10-

Serjik [45]

Answer:

0.007 M

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

$pH=-log(\sqrt{k_a\times C})$

Where, C is the concentration = ?

Given, pH = 3.45

So, for $CH_3COOH$ , $K_a=1.8\times 10^{-5}$

$3.45=-log(\sqrt{1.8\times 10^{-5}\times C})$

$\log _{10}\left(\sqrt{1.8\cdot \:10^{-5}C}\right)=-3.45$

C = 0.007 M

5 0

3 years ago

While eating dinner with her family, Tina's mother starts to cough. When Tina

EleoNora [17]

The correct answer is: C. “Tina’s mother has severe FBAO. Tina should begin administering back blows followed by abdominal thrusts if the problem persists.”

Explanation: I did my study and took the test, this was right. :)

6 0

3 years ago