Answer:
adding
opposite
Explanation:
dont blame me if u get them wrong
I am assuming that the balanced equation is
2H₂ + O₂ ⇒ 2H₂O
Since the hydrogen is the limiting reagent (meaning if the hydrogen runs out the reaction stops), we need to compare the mole ratio between hydrogen and water.
The mole ratio between H₂ and H₂O is 2:2, or 1:1 (as seen on the coefficients of the balanced equation)
And so for every mole of hydrogen, it will be equal to water. Since hydrogen is 4 moles, 4 moles of water would be created.
So we use the coefficients of H₂ and H₂O in order to answer this question.
Answer:
The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Explanation:
Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.
- The catalyst surface area is directly proportional to the reaction rate
- So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.
2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.
3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.
4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased
So, The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Answer: nothing. It remains undissolved
Explanation: saturated = dissolved as much solute as solvent can contain
