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White raven [17]
3 years ago
9

Hydrogen gas can be produced by reacting aluminum with sulfuric acid. How many moles of sulfuric acid are needed to completely r

eact with 15.0 moles of aluminum according to the following equation?
2Al+3H2SO4⟶Al2(SO4)3+3H2

Group of answer choices

0.100 mol

15.0 mol

10.0 mol

22.5 mol
Chemistry
1 answer:
Illusion [34]3 years ago
7 0

Answer:

22.5

Explanation:

all you have to do is take the number of moles of al and multiply them by sulfuric acids mole ratio as given in the equation (3), then divide by aluminums mole ratio number (2). then you will have moles of sulfuric acid.

*note: this only works if you are going moles to moles, if you are converting to anything else, this will NOT work*

if you have any questions leave them in the comments and i will try to answer them, if this helped, pls give a brainly

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How many grams is 10 moles of H2O?​
Elan Coil [88]

Answer:

So, 10 mole of water will weigh (18x10) = 180g.

5 0
3 years ago
Draw the structure(s) of the branched alcohol(s) with the chemical formula c5h12o.
xxTIMURxx [149]

A<em>nswer:</em>

The possible branched chain structure of alcohols with chemical formula C5H12O are following.

  • 3-methylbutan-2-ol
  • 3-methylbutan-1-ol
  • 2,2-dimethylpropan-1-ol
  • pentan-3-ol
  • 2-methylbutan-1-ol
  • 2-methylbutan-2-ol

Structure:

Please see attachment

Download docx
7 0
4 years ago
A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the perce
STALIN [3.7K]

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂

The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

5 0
3 years ago
If a photon has a frequency of 3.67 x 10^14 Hz, what is<br> its wavelength?
poizon [28]

Answer:

8.17 × 10^-7

Explanation:

You would divide 3 + 10^8 with 3.67 ×10^14, Which gives you the number 8.174369 = 8.17 :)

5 0
3 years ago
Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2, what is the limiting reactant?
omeli [17]

Answer:

O2

Explanation:

for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:

MM FeS2 = 120n  = 26.2g / 120g/mol = 0,218 mol

MM O2  = 32n = 5,44g/32g/mol = 0,17 mol

The limiting reactant is  

O2

8 0
3 years ago
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