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AysviL [449]
2 years ago
13

The distance from Clinton to Greenville is 124 miles. To find the speed of a car, use the expression d divided t, where d repres

ents the distance and t represents time. Find the speed of a car that travels from Clinton to Greenville in 2 hours
Mathematics
2 answers:
OLEGan [10]2 years ago
7 0
Here you go , hope it’s helps

Bezzdna [24]2 years ago
6 0

Step-by-step explanation:

time = 2 hours

distance travelled(d) = 124 miles

so

speed = d/t

=  124/2

= 62 miles per hour

Therefore, the speed of car is 62 miles per hour.

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dezoksy [38]

Answer:

Answer 3 (-6x-2y=12)

Step-by-step explanation: Turn to slope form to check

First- Add the 6x from both sides

-2y=6x+12

Second- Divide by two on both sides

y= -3x-6

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3 years ago
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Please help I'm struggling with this.<br>​
Mademuasel [1]

Answer:

thats thiccc

Step-by-step explanation:

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2 years ago
There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
3 years ago
Find the sum of -3a and 5a -3
zepelin [54]

Find the sum of -3a and 5a -3

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2a-3

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3 years ago
What is the sum of the geometric series in which A1 = 4, r = 3, and An = 324?
koban [17]
The answer would be 328
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3 years ago
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