6 half dollar coins would= $3.00 so you would add $3.00+$3.00=$6.00
Answer:
-3
this diagram might help you ( ◜‿◝ )♡
![\bf 3y=\cfrac{8-12y}{4}+2\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{12y=8-12y+8} \\\\\\ 12y=-12y+16\implies 24y=16\implies y=\cfrac{16}{24}\implies y=\cfrac{2}{3}](https://tex.z-dn.net/?f=%20%5Cbf%203y%3D%5Ccfrac%7B8-12y%7D%7B4%7D%2B2%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B4%7D%7D%7B12y%3D8-12y%2B8%7D%20%5C%5C%5C%5C%5C%5C%2012y%3D-12y%2B16%5Cimplies%2024y%3D16%5Cimplies%20y%3D%5Ccfrac%7B16%7D%7B24%7D%5Cimplies%20y%3D%5Ccfrac%7B2%7D%7B3%7D%20)
if you wonder why we multiplied by the LCD of 4, is just to do away with the denominators.
We will be using the fact that
, where
is the probability that the first bulb works and
is the probability that the second bulb works.
The probability that the first bulb works is
. However, when we take one out (given that the first bulb works) we now have 19 working bulbs and 4 bad ones. This means that the probability that the second bulb works is
.
Now, we can find our final probability:
![\dfrac{5}{6} \cdot \dfrac{19}{23} = \boxed{\dfrac{95}{138}}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B5%7D%7B6%7D%20%5Ccdot%20%5Cdfrac%7B19%7D%7B23%7D%20%3D%20%5Cboxed%7B%5Cdfrac%7B95%7D%7B138%7D%7D%20)
Answer: -16, 81, 19
Step-by-step explanation:
f(x)=-16x^2+81x+0
19 feet