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Vikentia [17]
3 years ago
15

PLS HELP!! GIVING BRAINLIST!!

Mathematics
2 answers:
7nadin3 [17]3 years ago
6 0

Answer:

f = 4n

f = n+27

Fred is 36 years old and Nathan is 9 years old.

n = 9

Step-by-step explanation:

atroni [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Ooh I love these type of problems

Okay, here we go :

f = Fred and n = Nathan

  f = 4n

  f = n + 27

Above are the two equations (the words translated into algebra)

Now you can solve using substitution (any method works, but substitution is easiest for this problem)

4n = n + 27

3n = 27

n = 9

Since n = 9 substitute n into either equation

f = 4 * 9

f = 36

Fred is 36 and Nathan is 9

lol :)

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3 years ago
"You measure 34 dogs' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 13.5 o
liraira [26]

Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{13.5}{\sqrt{34}} = 4.54

The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.

The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

7 0
3 years ago
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Zolol [24]
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3 years ago
The second of 2 numbers is 5 more than twice the first. Their sum is 29. Find the numbers. (With steps)
hodyreva [135]
So the equation is x + 2x + 5= 29
Here are the steps            -5    -5
                               -----------------------
                                        3x   = 24
      Divide both sides by 3 so you get
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Then look back at the question, the second number has to be twice that number plus 5
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8 0
3 years ago
równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0
2 years ago
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