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Gwar [14]
3 years ago
13

Help on 9 & 10 please!

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Step-by-step explanation:

9. x and z are equal. y+z=90

   148-x=180 x+148 are supplementary

   -148    -148 Subtract 148 from both sides to isolate x

         x=32 degrees

         z=32 degrees b/c x and z are equal

 y+z=90 y and z are complementary

 y+(32)=90 Substitute 32 in for z

   -32     -32

 y         =58 degrees

10. (4x-25)=(2x+7) B/c of the bisection, the two angles are equal.

     4x-25  =2x+7 Remove parenthesis

      -2x       -2x Subtract 2x from both sides

     2x-25  =    +7

          +25       +25 Add 25 to both sides to isolate x

    2x         =     32

     /2                 /2 Divide both sides by 2 to isolate x

     x            =     16

 (4(16)-25)+(2(16)+7)=78 degrees Substitute 16 into the equation, this time adding the values instead of setting them equal to get the angle measure requested.

11. (6x-47)+(x+4)=90 Angles that are complementary add up to 90 degrees

    7x-43            =90 Add like terms

         +43             +43 Add 43 to both sides to isolate x

   7x                    =133

   /7                       /7 Divide both sides by 7 to isolate x

     x                     =19

((19)+4)=23 degrees Substitute x into the angle measure requested

12. 180=2x-9+x Use the words to help you determine what each value is.

     180=3x-9 Add like terms

     +9        +9 Add 9 to both sides to isolate x

     189=3x

     /3     /3 Divide both sides by 3 to isolate x

     63=x

 2(63)-9=177 degrees Substitute 63 into x to find the requested angle measure.

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Second graph is a parabola, so it is the graph of a quadratic function.

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Answer:

1) Zero based on (-16·t - 2) is t = -1/8 second

2) Zero based on (t - 1) is t = 1 second

Step-by-step explanation:

The given functions representing the height of the beach ball the child throws as a function of time are;

y = (-16·t - 2)·(t - 1) and y = -16·t² + 14·t + 2

We note that (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

Therefore, the function representing the height of the beachball, 'y', is y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The zeros of a function are the values of the variables, 'x', of the function that makes the value of the function, f(x), equal to zero

In the function of the question, we have;

y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The above equation can be written as follows;

y = (-16·t - 2) × (t - 1)

Therefore, 'y' equals zero when either (-16·t - 2) = 0 or (t - 1) = 0

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(-16·t - 2) = 0

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The zero based on (-16·t - 2) is t = -1/8 second

2) The zero based on (t - 1) = 0, is given as follows;

(t - 1) = 0

∴ t = 1 second

The zero based on (t - 1) is t = 1 second

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