Answer: 620≥ 427.57+ 11.38(4)+ (31.41) +57.75x
Step-by-step explanation:
So our limit is the 620$ that he has to spend. We know for a fact that the bike costs about 427.57 dollars. 4 $11.38 reflectors are purchased as well as gloves for 31.41. Now however many outfits he can purchase cannot exceed or go over his money limit of 620 so the variable (x) represents how many outfits he can buy without going over.
2(-20)+3[5/4(-20)]
-40 + 3[-25]
-40 + -75
-115
-115 is your final answer.
<h3>
Answer: Q = 8</h3>
====================================================
Explanation:
The left hand side of the first equation is x-3y
The left hand side of the second equation is 2x-6y = 2(x-3y). Note how it's simply double of the first expression x-3y
If we multiply both sides of the first equation by 2, we get
x-3y = 4
2(x-3y) = 2*4
2x-6y = 8
Meaning that 2x-6y = 8 is equivalent to x-3y = 4. Both produce the same line leading to infinitely many solutions. Each solution will lay along the line x-3y = 4.
We can say each solution is in the set {(x,y): x-3y = 4}
Which is the same as saying each solution is of the form (3y+4,y)
X - speed of the current
40+x - speed with current
40-x - speed against current
t-time
(40+x)*t=100
(40-x)*t=60
40t+xt=100
<span> + 40t-xt = 60
</span> 80t =160
t = 2
40t+xt=100,
40*2+2x=100
80+2x=100
2x=100-80
2x=20
x=10 mi/h
10 mi/h speed of the current.
5,00000 so that is the answer
