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Serhud [2]
3 years ago
5

If x>0 and y<0 where is the (x,y) point located

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:

If x > 0 and y < 0, the point (x, y) must be located in Quadrant IV.

Hope it helps

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Which graph represents a function
ICE Princess25 [194]

Answer:

the bottom left one (the graph that looks like a circle) is not a function, but the other ones are.

Step-by-step explanation:

A function is defined so that for every x value within a function has a y value.  This means that an x value CANNOT have more than one y value.  The bottom right one has two y values for almost every x value within the domain.  The top ones are functions, because all x values have only 1 y value (a discontinuous function is still a function!)  And the bottom right is too.

3 0
3 years ago
Calculate the value of the sample variance. Round your answer to one decimal place. 9_5,9_5,2,9_5
Ugo [173]

Answer:

s^2 = 0.01

Step-by-step explanation:

Given

Values: 9/5, 9/5, 2, 9/5

Required

Calculate the sample variance

Sample variance is calculated using:

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1}

First, we calculate the mean

\overline x = \frac{\sum x}{n}

\overline x = \frac{9/5 + 9/5 + 2 + 9/5}{4}

\overline x = \frac{7.4}{4}

\overline x = 1.85

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1} becomes

s^2 = \frac{(9/5 - 1.85)^2+(9/5 - 1.85)^2+(2 - 1.85)^2+(9/5 - 1.85)^2}{4 - 1}

s^2 = \frac{(-0.05)^2+(-0.05)^2+(0.15)^2+(-0.05)^2}{4 - 1}

s^2 = \frac{0.0025+0.0025+0.0225+0.0025}{3}

s^2 = \frac{0.03}{3}

s^2 = 0.01

<em>Hence, the variance is 0.01</em>

5 0
3 years ago
9. Which of the following is true about the Venn diagram below?
bonufazy [111]

Answer:

(d) All of the above

Step-by-step explanation:

In order to solve this question we will have to find out which numbers are located in which group (the group of numbers are U, B, B').

So lets start of with finding out what numbers are a part of group U. By looking at that picture we can see that all number on the graph are a part of group U. So.....

U = {0,1,2,3,4,5,6,7,8,9}

Then we can find out what numbers are part of the group B. We just have to include the numbers that are located within the circle and exclude all of the numbers out side of the circle. So........

B = {0,1,4,5,6,7,8}

We find numbers that are parts of group B' by using a similar method that we used to find out what numbers were part of group B (Just this time we include all numbers outside of the circle and exclude all of the numbers inside the circle). So ......

B' = {2,3,9}

Now we see that the right option is option d.

5 0
3 years ago
Simplify. 12+(38−18)2
julia-pushkina [17]
The answer is 52. remember PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction) you can use "please excuse my dear aunt sally" to help you remember!  :)
3 0
3 years ago
Read 2 more answers
An equation is shown below:
IrinaK [193]
5(2x - 8) + 15 = -15
               -15      -15     subtract 15 from each side
5(2x - 8) = -30
  ÷5             ÷5             divide both sides by 5
2x - 8 = -6
     +8    +8                   add 8 to each side
2x=2
÷2  ÷2                          divide both sides by 3
x = 1

Checking:
5(2(1)-8) + 15 = -15
5(-6) + 15 = -15
-30 + 15 = -15
-15 = -15             Correct! x=1
7 0
4 years ago
Read 2 more answers
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