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3 years ago

Which graph represents a function

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

3 0

Answer:

the bottom left one (the graph that looks like a circle) is not a function, but the other ones are.

Step-by-step explanation:

A function is defined so that for every x value within a function has a y value. This means that an x value CANNOT have more than one y value. The bottom right one has two y values for almost every x value within the domain. The top ones are functions, because all x values have only 1 y value (a discontinuous function is still a function!) And the bottom right is too.

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(-2.1m-5)+(3m-7)<br> Find the sum

wolverine [178]

Answer:

0.9 m − 12

Note:

Since there is no y value m can not be determine. Therefore finding the sum here can not be determined so instead you can try simplifying

4 0

3 years ago

Read 2 more answers

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

4 years ago

The volume of a cone varies jointly as the square of its radius and its height. if the volume of a cone is 99piπ cubic inches wh

tatyana61 [14]

Any answer choices ?

7 0

3 years ago

A case of 8 items costs $9.44 at Costco. What is the price of each item?

Anarel [89]

Answer: $1.18 per item

Step-by-step explanation:

9.44/8=$1.18 per item

5 0

2 years ago

PLEASE HELP ME!!!!!

solong [7]

The full workings for the house purchase you made on a mortgage are as follows:

1. Price of House = $499,000 (given)

2. Down Payment = $99,800 ($499,000 x 20%)

3. Amount Financed (Mortgage principal) = $399,200 ($499,000 - $99,800).

4. Monthly Payment = $2,522.94 (given)

5. Number of monthly payments = 360 months (30 x 12)

6. Total Payback = $908,258.40 ($2,522.94 x 360)

7. Total Interest = $509,058.40 ($908,258.40 - $399,200)

8. Assessed Valuation = $199,600 ($499,000 x 40%)

9. Real Estate Taxes (annual) = $6,047.88 ($199,600 x $3.03/$100)

10. Escrow Payment Per month (taxes & insurance) = $628.99 ($6,047.88 + $1,500)/12

11. Monthly Payment to lender (escrow + mortgage) = $3,151.93 ($628.99 + $2,522.94)

<h3>What is a mortgage?</h3>

A mortgage is a loan arrangement that allows a borrower to buy some property, usually a house, without paying for the full cost immediately.

The borrower then makes a monthly payment, which includes the principal and its interest.

Learn more about mortgage payments at brainly.com/question/22846480

#SPJ1

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2 years ago