Answer:
sorry i did not see my link
Step-by-step explanation:
I think the answer is 1.2
Set up a proportion: (1/4)/6 = 32/x
Cross multiplying, we have (1/4)x = 192
x = (4)(192) = 768 miles
Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion: 
Significance level : 
Critical z-value :
(using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

i.e. 
i.e. 
i.e. 
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)