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Katarina [22]
3 years ago
15

Which of the following can be the side lengths of a triangle?

Mathematics
1 answer:
kogti [31]3 years ago
7 0
<span>In a triangle the sum of two sides is always greater than the third side.

</span><span>A:12,9,21
</span><span>12+9 = 21
21 = 21  </span>⇒  no

<span>B:7,6,12
</span>7+6 = 13
13 > 12  ⇒  yes

<span>C:3,8,14
</span>3+8 = 11
11 < 14  ⇒  no

<span>D:23,13,37
</span>23+13= 36
36 < 37  ⇒  no

Answer: <span>B:7,6,12</span>
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Step-by-step explanation:

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What is the greatest common factor of 38 and 59
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Factors of 38

1, 2, 19, 38
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1×38
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Factors of 59

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GCF of 38 and 59

1 is the both the common and GCF of 38 and 59



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2 years ago
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Find csc x if sin x + cot x cos x =√3.
Oksi-84 [34.3K]

Answer:

The answer is (d) ⇒ cscx = √3

Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

∵ 1/sinx = cscx

∴ cscx = √3

7 0
3 years ago
jamal's school is having a bake sale today at lunch and he agreed to bring four dozen cupcakes in for sale. to catch his bus he
Vesna [10]

Answer:

They will finish in time for Jamal to catch the bus.

Step-by-step explanation:

Jamal agreed to bring four dozen i.e. 48 cupcakes in for sale.

He started icing cupcakes at 7:40 a.m. at a rate of 3 cupcakes per minute up to 7:50 a.m. that is the time when he needs to be out of his house to catch his bus.

So, with in this 10 minutes (7:40 a.m. to 7:50 a.m.) he would be able to make (10 × 3) = 30 cupcakes.

Now, at 7:44 his older sister started icing cupcakes too. she iced them at a rate of 4 cupcakes per minute.

So, in this 6 minutes (7:44 a.m. to 7:50 a.m.) she will be able to make (4 × 6) = 24 cupcakes.

Therefore, in total Jamal will be able to made (30 + 24) = 54 cupcakes.

Since, 54 > 48 so, they will finish in time for Jamal to catch the bus. (Answer)

3 0
3 years ago
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