Answer:
Mass of oxygen = 2.2 g
Explanation:
Given data:
Mass of benzoic acid= 8.20 g
Mass of oxygen= ?
Solution:
Molar mass of oxygen = 16×2 g/mol
Molar mass of C₆H₅COOH = 7×12 + 1×6 + 2×16
Molar mass of C₆H₅COOH = 84 + 6 + 32
Molar mass of C₆H₅COOH = 122g/mol
Mass of oxygen in 8.20 g of C₆H₅COOH :
Mass of oxygen = 32 g.mol⁻¹/122 g.mol⁻¹ × 8.20 g
Mass of oxygen = 2.2g
Molarity = moles / liter of solution
Given, Moles of Fe³⁺ = 0.200
Volume of solution = 725 ml = 0.725 L
Conversion factor: 1000 ml = 1L
Molarity = 0.200 / 0.725 L = 0.275 M
The dissociation of Fel₃ in water is ad follows:
Fel₃ → Fe³⁺ + 3l⁻
1 mole of Fel₃ gives 1 mole of Fe³⁺ ions and 3 moles of l⁻
Since the solution is 0.275 M of Fel₃, so there are 0.275 M of Fe³⁺ ions,
and (3 x 0.275 M) = 0.825 M of l⁻ ions.
For the following question(s), consider a 4% starch solution and a 10% starch solution separated by a semipermeable membrane.
Which of the following also occurs in this system?
There is a net flow of water from the 4% starch solution into the 10% starch solution
<span>According to Mendeleyev-Klapeyron’s equation
pV = nRT,
where p = 160 atm V = 12 R -constant 0.0821 & T = 298 in Kelvin
Using given data, we can determine the amount of Helium gas:
n = pV/RT = (160â™12)/(0,0821â™298) = 78,48 (mol)
For atmospheric pressure (1 atm) and the same amount we can calculate the volume of tank, using previous equation:
V = nRT/p = (78,48â™0,0821â™298)/1 = 1920 (liters)
V = 1920 liters
Thus Answer is 1920 liters</span>
