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Korvikt [17]
3 years ago
10

Wuy Piolcululugu Give the names of two organs in the chest. 1. ............... 2 m

Chemistry
1 answer:
Arada [10]3 years ago
8 0

Answer:

The organs present inside the chest are :

1. The lungs

2. The heart

Explanation:

The chest cavity is also called as the thoracic cavity. It is the second largest hollow space of the body.In the bottom , it is enclosed by the diaphragm.

This cavity actually contain three space each round with mesothelium , pleural cavity and precardial cavity.

This contain the lungs , the tracheobronchial tree , the heart , the blood vessels which transport the blood between the heart and the lungs.

It also contain the esophagus .

Esophagus is the path through which the food passes from the mouth to the stomach.

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A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t
7nadin3 [17]

Answer:

m=69.3kg

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

V=22.3gal*\frac{3.78541L}{1gal}=84.415L

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

m=0.8206g/L*84.415L\\\\m=69.3kg

Best regards!

8 0
3 years ago
How many moles of al does 13.49 g of al represent?
Harlamova29_29 [7]
Use equation
number of moles= sample mass/molar mass
7 0
2 years ago
True or False - when setting up your conversion problems every numerical value must have a unit on it.
Anastaziya [24]
I think its true but im not 100 percent sure 
3 0
2 years ago
The ph of a 0.0100 m solution of the sodium salt of a weak acid is 11.00. what is the ka of the acid?
Vitek1552 [10]
The answer is Ka = 1.00x10^-10.
Solution:
When given the pH value of the solution equal to 11, we can compute for pOH as
     pOH = 14 - pH = 14 - 11.00 = 3.00
We solve for the concentration of OH- using the equation
     [OH-] = 10^-pOH = 10^-3 = x

Considering the sodium salt NaA in water, we have the equation
     NaA → Na+ + A- 
hence, [A-] = 0.0100 M

Since HA is a weak acid, then A- must be the conjugate base and we can set up an ICE table for the reaction
                             A- + H2O ⇌ HA + OH-
     Initial             0.0100            0       0
     Change        -x                    +x     +x
     Equilibrium    0.0100-x         x       x

We can now calculate the Kb for A-:
     Kb = [HA][OH-] / [A-] 
           = x<span>²</span> / 0.0100-x
Approximating that x is negligible compared to 0.0100 simplifies the equation to
     Kb = (10^-3)² / 0.0100 = 0.000100 = 1.00x10^-4

We can finally calculate the Ka for HA from the Kb, since we know that Kw = Ka*Kb = 1.0 x 10^-14:
     Ka = Kw / Kb 
           = 1.00x10^-14 / 1.00x10^-4
           = 1.00x10^-10
7 0
3 years ago
How many molecules of CO are produced when 2.73 moles of HPO3 react? 4HPO3 + 12C ----&gt; 2H2 + 12CO + P4
Zina [86]
According to the balanced chemical equation:
4 HPO₃ + 12 C → 2 H₂ + 12 CO + P₄
4 moles of HPO₃       ---gives---> 12 moles of CO
2.73 moles of HPO₃  ---gives---> ? moles of CO
so number of moles of CO = \frac{(2.73 * 12)}{4} = 8.19 moles of CO
Number of molecules of CO = number of moles * Avogadro's number
                                       = 8.19 * (6.022 * 10²³) = 4.93 * 10²⁴ molecules
3 0
3 years ago
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