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Korvikt [17]
3 years ago
10

Wuy Piolcululugu Give the names of two organs in the chest. 1. ............... 2 m

Chemistry
1 answer:
Arada [10]3 years ago
8 0

Answer:

The organs present inside the chest are :

1. The lungs

2. The heart

Explanation:

The chest cavity is also called as the thoracic cavity. It is the second largest hollow space of the body.In the bottom , it is enclosed by the diaphragm.

This cavity actually contain three space each round with mesothelium , pleural cavity and precardial cavity.

This contain the lungs , the tracheobronchial tree , the heart , the blood vessels which transport the blood between the heart and the lungs.

It also contain the esophagus .

Esophagus is the path through which the food passes from the mouth to the stomach.

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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
What is the abrviation of the element gold on the periodic table.
Natalka [10]

Au is the abbriviation


Hope this helps Buddy!


- Courtney

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a set of pulleys is used to lift a piano weighing 1,000 netwons. the piano is lifted 3 meters in 60 seconds. How much power is u
DENIUS [597]

P = W/t

P = F.s/t

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6 0
2 years ago
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Write a chemical equation for the following reaction. (Type your answer using format CH4 for CH4.) In water, iron(III) chloride
taurus [48]

Answer:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

3NaCl(aq)

Explanation:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

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7 0
3 years ago
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