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Nataliya [291]
3 years ago
9

Please check my answer! Due in a few minutes!

Chemistry
2 answers:
rewona [7]3 years ago
8 0

Answer:

Explanation:

It is A. that is the only one that really makes any sense to me.

I do hope I helped you! :)

Gwar [14]3 years ago
6 0

Answer:

write a hypothesis

Explanation:

in a lb procedure a hypothesis is most likely useful whaen doing science

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Which statement is best supported by the information in the chart?
bezimeni [28]

Answer:

B

Explanation:

Because , it is the answer .

3 0
3 years ago
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Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca(NO3)2 + 2 AgCl All
HACTEHA [7]

Answer:

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and  finally calculate the mass of AgCl.

                      2 AgNO₃   + CaCl₂    ⇒   Ca(NO₃)₂   + 2 AgCl

mass, g                  6.97        6.39                                     ?

MW ,g/mol         169.87      110.98                                  143.32

mol =m/MW           0.10         0.06                                    0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

0.10 mol x 143.32 g/mol = 14.33 g

5 0
3 years ago
A 29.7 g sample of iron ore is treated as follows. The iron in the sample is all converted by a series of chemical reactions to
Softa [21]

<u>Answer:</u> The mass of iron in the ore is 10.9 g

<u>Explanation:</u>

We are given:

Mass of iron (III) oxide = 15.6 g

We know that:

Molar mass of Iron (III) oxide = 159.69 g/mol

Molar mass of iron atom = 55.85 g/mol

As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.

To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:

In 159.69 g of iron (III) oxide, mass of iron present is (2\times 55.85)=111.7g

So, in 15.6 g of iron (III) oxide, mass of iron present will be = \frac{111.7g}{159.69g}\times 15.6g=10.9g

Hence, the mass of iron in the ore is 10.9 g

7 0
3 years ago
How many atoms of oxygen is in CO2?
rosijanka [135]

Answer: 2 atoms

Explanation: 2 in Co2 means 2 atoms

7 0
3 years ago
A balloon was partially filled with helium gas at room temperature. It occupied 4.0 liters of volume at 700.0 mmHg atmospheric p
Tatiana [17]

Answer:

28.28 L.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have two different values of V and P:

<em>P₁V₁ = P₂V₂</em>

<em></em>

P₁ = 700.0 mm Hg, V₁ = 4.0 L.

at burst: P₂ = 99.0 mm Hg, V₂ = ??? L.

<em>∴ V₂ = P₁V₁/P₂</em> = (700.0 mm Hg)(4.0 L)/(99.0 mm Hg) = <em>28.28 L.</em>

3 0
3 years ago
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