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3 years ago

15

5TH GRADE LEVEL QUESTION. LOOK AT PHOTO AND LIST BY STEP 1 2 AND 3. GIVING BRAINLIEST.

1 answer:

Ivan3 years ago

8 0

Answer:

Step 1: 3x4+6

Step 2: 25-18

Step 3: 7

Step-by-step explanation:

You might be interested in

How many oz of nuts are there in a box that holds 3.2 pounds

melisa1 [442]

Answer:

51.2 oz

Step-by-step explanation:

Stoichiometry

3.2 lb x 16 oz

÷ 1 lb =51.2 oz

3 0

4 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

3 years ago

I need the answers to these if you can’t read it it says “You drink 16 Fluid ounces of milk for breakfast every morning”.

Reika [66]

Answer: A. y = 16 x

B. 8 days

Step-by-step explanation:

A) Here, 16 Fluid ounces of milk is used for breakfast every morning.

In one day the consumption of milk = 16 fluid ounces

In x days the consumption of milk = 16 x fluid ounces

Thus, if y be the total milk in ounces that is used in x days,

The required function,

y = 16 x

B) In 1 day, consumption of milk = 16 ounces

⇒ $16\text{ ounces milk } = 1 \text{ day}$

⇒ $8\times 16\text{ ounces milk } = 8\times 1 \text{ day}$

⇒ $128\text{ ounces milk } = 8 \text{ day}$

Since, 128 ounces = 1 gallon

⇒ $1\text{ gallon milk } = 8 \text{ day}$

In 8 days, 1 gallon of milk will consumed.

4 0

4 years ago

Please help me as soon as posable!! In hurry!!(24 points)

attashe74 [19]

The sequence is geometric, so

$a_n = r a_{n-1}$

for some constant r. From this rule, it follows that

$a_3 = r a_2 \implies 20 = 2r \implies r = 10$

and we can determine the first term to be

$a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15$

Now, by substitution we have

$a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots$

and so on down to (D)

$a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15$

(notice how the exponent on r and the subscript on a add up to n)

4 0

2 years ago

How to simplify the expressions of 5p-5-10-2p

Arada [10]

Answer:

3p - 15

Step-by-step explanation:

5p - 2p = 3p

-5 - 10 = -15

3p + - 15 = 3p - 15

4 0

3 years ago