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lina2011 [118]
2 years ago
12

Each student in a classroom has chosen either a green, red, or blue marble and written their initials on it. In addition, some o

f the marbles have the letter A written on them, and some of the marbles have the letter B written on them. All of the marbles are shown below. All of the marbles are placed in a bag, and then one is randomly selected.
(the picture wouldn't upload)
A. The probability that the selected marble will have a B written on it is ___ .

B. The probability that the selected marble will be green is points ____.
Mathematics
1 answer:
Crazy boy [7]2 years ago
6 0

Answer:

a: 40 percent

b: 30 percent

i think

Step-by-step explanation:

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HELP PLEASE I GOT CACA WIFI
Brut [27]

Answer:28

Step-by-step explanation:

hope this helpes

3 0
2 years ago
A 208-yard-long road is divided into 16 parts of equal length. Mr. Ward paints a 4-yard-long strip in each part. How long is the
laila [671]

We have been given that a 208-yard-long road is divided into 16 parts of equal length.

Let us find length of each part.

\text{Length of each part}=\frac{208}{16}

\text{Length of each part}=13

Length of each part will be 13 yards.                

We are told that Mr. Ward paints a 4-yard-long strip in each part.

Now we will subtract length of painted strip from length of each equal part to find length of unpainted strip of each part of the road.

\text{Length of unpainted strip}=13-4

\text{Length of unpainted strip}=9    

Therefore, length of each unpainted strip will be 9 yards.

5 0
3 years ago
Dylan is evaluating the expression 13 + 19 + 7 + 10. At one step in his work, Dylan rewrites the equation as 13 + 7 + 19 + 10. W
AlekseyPX

Answer:

Communicative Property

Step-by-step explanation:

The communicative property is basically just switching numbers around but still leading to the same answer, if you could see, both of the equations lead to the same answer, 49. Here is a chart to help you out.

7 0
3 years ago
A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte
allsm [11]

Answer:

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

E_i = \frac{100}{5}= 20

The statsitic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0
2 years ago
Stephan is planning a hiking trip at Kings Canyon National Park. He plans to hike 14 miles every 2 days. If he hikes 42 miles, h
Stels [109]
Well for THIS one you'd have to find how many miles he hikes in ONE day, so you would divide 14 by 2 to get 7 miles per day, and to find how many days he hiked in 42 miles, just divide 42 divided by 7 which equals 6, so it took him 6 days to hike 42 miles. =)
I hope I helped! =D
8 0
3 years ago
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