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devlian [24]
3 years ago
10

Answer the question to become the brainliest

Mathematics
1 answer:
Sloan [31]3 years ago
4 0

Answer:

y = - 2x + 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 2, then

y = - 2x + c ← is the partial equation

To find c substitute (1, 7) into the partial equation

7 = - 2 + c ⇒ c = 7 + 2 = 9

y = - 2x + 9 ← equation of line

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ikadub [295]

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= 93525 + 3741

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3 0
3 years ago
PLEASE HELP NEED THIS ONE TO PASS
Ghella [55]

Answer:

x  = 4.

Step-by-step explanation:

We see that it passes through the x axis at  the point (4, 0) so x = 4 is a solution.

Check by solving the equation

x^2 - 4x + 13 = 13

Subtract 13 from both sides:

x^2 - 4x = 0

x(x - 4) = 0

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6 0
4 years ago
Read 2 more answers
Write the equation of the line parallel to the y axis at a distance of 7 units form it to is left​
Finger [1]

Answer:

x = -7

Step-by-step explanation:

Two parallel lines are lines that never intersect each other.

The y-axis can be written as x = 0.

Then if we want a parallel line to this one, it must be something like x = b

such that b ≠ 0.

Now we want that the distance between our line and the line x = 0 is 7 units to the left

(remember that the left is the negatie side of the axis)

then we can write:

b - 0 = -7

b = -7

The parallel line is x = -7

6 0
3 years ago
Factor by gcf 6x2+3x+21 The 2 is supposed to be small.
nexus9112 [7]

Given:

The expression is:

6x^2+3x+21

To find:

The factor of the given expression by GCF.

Solution:

It is given that,

6x^2+3x+21

The terms of the given expression are 6x^2,3x,21. The greatest common factor of these terms is 3.

6x^2+3x+21=3\times 2x^2+3\times x+3\times 7

So, taking out the GCF, the given expression can be rewritten as:

6x^2+3x+21=3(2x^2+x+7)

Therefore, the factor form of the given expression by GCF is 3(2x^2+x+7).

7 0
3 years ago
Look at pic and answer pls
PtichkaEL [24]

(a)  x^{-5}

(b)  3x^{-7}

(c)  $\frac{4}{3}x^4

Solution:

To write each of the given expression in the form ax^n:

(a)  \frac{x^3}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

$\frac{x^3}{x^8}=x^{3-8}

$\frac{x^3}{x^8}=x^{-5}

(b) \frac{6x}{2x^8}

Divide numerator and denominator by the common factor 2, we get

$\frac{6x}{2x^8}=\frac{3x}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

      $=3x^{1-8}

$\frac{6x}{2x^8} =3x^{-7}

(c)  \frac{28x^6}{21x^2}

Divide numerator and denominator by the common factor 7, we get

$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

        $=\frac{4}{3}x^{6-2}

$\frac{28x^6}{21x^2}=\frac{4}{3}x^4

8 0
3 years ago
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