The answer is 6 with a remainder of 1. (6 R.1)
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Answer:
1. D
2. A
Step-by-step explanation:
Q1. Kerry is simplifying ![5\cdot 10^{-3}](https://tex.z-dn.net/?f=5%5Ccdot%2010%5E%7B-3%7D)
By the definition of negative powers,
![a^{-n}=\dfrac{1}{a^n}](https://tex.z-dn.net/?f=a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D)
Hence,
![10^{-3}=\dfrac{1}{10^3}](https://tex.z-dn.net/?f=10%5E%7B-3%7D%3D%5Cdfrac%7B1%7D%7B10%5E3%7D)
So, the first step in simplifying the expression is
![5\cdot 10^{-3}=5\cdot \dfrac{1}{10^3}](https://tex.z-dn.net/?f=5%5Ccdot%2010%5E%7B-3%7D%3D5%5Ccdot%20%5Cdfrac%7B1%7D%7B10%5E3%7D)
Q2. Given the expression
![\dfrac{8}{10^{-2}}](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B10%5E%7B-2%7D%7D)
First, use the definition of negative powers:
![10^{-2}=\dfrac{1}{10^2}](https://tex.z-dn.net/?f=10%5E%7B-2%7D%3D%5Cdfrac%7B1%7D%7B10%5E2%7D)
Thus,
![\dfrac{8}{10^-2}=\dfrac{8}{\frac{1}{10^2}}=8\cdot 10^2=8\cdot 100=800](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B10%5E-2%7D%3D%5Cdfrac%7B8%7D%7B%5Cfrac%7B1%7D%7B10%5E2%7D%7D%3D8%5Ccdot%2010%5E2%3D8%5Ccdot%20100%3D800)
Easy, just write out the multiple of the numbers.
4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60
7: 7,14,21,28,35,42,49,56,63,70
Etc.
But a few common multiples:
28,56,84,112,140
These are the first 5 common multiples of 4 and 7.
Answer:
Step-by-step explanation: