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3 years ago

If the domain of the function f(x) = x - 5 is {1, 3, 4, 6} what is the range? F

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

Answer:

-4, -2, -1, 1

Step-by-step explanation:

If the domain is given we use the equation to determine the range but usually the range would be everything in this equation.

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What is the least common denominater of 3/4 and 7/10

klemol [59]

Answer:

Least Common Multiple of 3 , 4 and 7 is 84 .

Step-by-step explanation:

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3 years ago

Read 2 more answers

Evaluate the expression when p = 9.3 and q = –2.1.

guajiro [1.7K]

It's A 15.6
I know it's late but i hope i helped :D

6 0

4 years ago

Which set of population data is the least dispersed from its mean? 2, 3, 2, 9 4, 0, 4, 0 6, 2, 2, 2 9, 3, 5, 3.

exis [7]

The set of data 6, 2, 2, 2 will have the least dispersion from its mean.

From four sets of data, we take the mean of 6,2,2,2

$\rm mean =\dfrac{ Sum \ of\ data}{Number \ of\ data}$

So the mean will be

$\rm mean =\dfrac{ 6+2+2+2}{4}=\dfrac{12}{4} =3$

So the mean of the data (6,2,2,2) is 3 which has the least dispersion from its every data as compared to the other data

Thus the set of data 6, 2, 2, 2 will have the least dispersion from their mean.

<h3 />

To know more about mean follow

brainly.com/question/1136789

7 0

2 years ago

Simplify: (x+4)*(2x+5

s344n2d4d5 [400]

Answer:

2x^2+13x+20 is the simplified answer

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3 years ago

The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0

3 years ago