Hundredths place, tenths place, and ones place
Answer:
You kayak 255 feet farther 5 minutes on the way down the river than in 5 minutes on the way up the river
Step-by-step explanation:
Given:
The rate at which you kayak up a river = 48 feet every 30 seconds.
The rate at which you kayak down a river = 423 feet every 3 minutes
To Find:
How much farther do you kayak in 5 minutes on the way down the river than in 5 minutes on the way up the river = ?
Solution:
Let the speed with which you kayak up the river be x and the speed with which you kayak down the river be y
Then
x =
[ Converting 30 seconds to 0.5 minutes]
x = 96 feet per minute
Similarly
y =
y = 141 feet per minute
Now the distance kayaked up the river in 5 minutes
=>
=>
( in 5 minutes there are 10 30 minutes)
=>960 feet
Now the distance kayaked down the river in 5 minutes
=>
=>
( in 5 minutes there are 10 30 minutes)
=>705 feet
Thus
960-705 = 255 feet
Answer:
4/1 or 4
Step-by-step explanation:
20/5 share only 2 divisible number in common 1 and 5.
the greatest of those being 5
divide them both by 5 and you get 4/1 or 4.
Answer:
$163.54
Step-by-step explanation:
Volume of rectangular container = 10m^3
Length = 2(width)
Material for the base cost $10 per square meter
Material for the side cost $6 per square meter
Volume = L*B*H
L= 2W
V = (2W).W. H
10 = 2W^2.H
H = 10 /2W^2
H = 5/W^2
Let C(w) = cost function
C(w) = 10(L.W) + 6(2.L.H + 2.W.H)
= 10(2W.W) + 6(2.2W.H + 2.W.H)
= 10(2W^2) + 6(4W.H + 2.W.H)
= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)
= 20W^2 + 6(20/W + 10/W)
= 20W^2 + 6((10+20)/W)
= 20W^2 + 6(30/W)
C(w) = 20W^2 + 180/W
To find the minimum value, differentiate C with respect to w
C'(w) = 40W - 180/W^2
Put C'(w) = 0
0 = 40W - 180/W^2
40W = 180/W^2
40W^3 = 180
W^3 = 180/40
W^3 = 4.5
W = cube rt(4.5)
W = 1.65m
C = 20(1.65)^2 + 180/1.65
C = 54.45 + 109.09
C= $163.54
Minimum cost = $163.54
Answer:amamsjhshsbdbd
Step-by-step explanation:
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