1) X^5Y/X^5= X^0Y= Y (Anything raise to power of 0 is 1)
2)(3mn)^1= 3mn
3)m^-4xM^5= M^-4+5= M
4) 5^-4x5^4= 5^-4+4= 5^0= 1
5) nm^3/n^3m= n^1-3m^3-1= n^-2m^2= m^2/n^2
6) (-2)^0= 1
therefore number 4 and 6 has the value of 1
Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
Answer:
n=10
Step-by-step explanation:
-2=-n+8
-n=-10
n=10
$10 / 8 = 1.25
Soo...
$6 x 1.25 = 7.50