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julia-pushkina [17]
2 years ago
5

Please answer asap!!!

Mathematics
1 answer:
Scilla [17]2 years ago
8 0

Answer:

z = 66

Step-by-step explanation:

RS = z

QT = z - 33

Based on the midsegment theorem, QT = ½(RS)

Plug in the values

z - 33 = ½(z)

Multiply both sides by 2

2(z - 33) = z

2z - 66 = z

Add 66 to both sides

2z = z + 66

Subtract z from both sides

2z - z = 66

z = 66

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Ezekiel bought a 18 ounce box of chocolate for $6.50. What was the cost per ounce? in a explanation order
vivado [14]

Answer:0.36

Step-by-step explanation:

You divide 18 by 6.50, that give you the cost per ounce

7 0
3 years ago
What is the distance between 23 and -8 on a number line?
elena55 [62]

Answer: 31

Step-by-step explanation:

To find the distance, find the difference between the number.

23 - (-8) = 31     So the distance is 31  units.

Note: To go from -8 to 23   you will have to add 31 to -8  and to go from  23 to -8 you will have to subtract 31 so the distance is 31

7 0
3 years ago
We have 4different boxesand 6different objects. We want to distribute the objects into the boxes such that at no box is empty. I
Musya8 [376]

Answer:

Following are the solution to this question:

Step-by-step explanation:

They provide various boxes or various objects.  It also wants objects to be distributed into containers, so no container is empty.  All we select k objects of r to keep no boxes empty, which (r C k) could be done.  All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining (r-k) objects. All can be put in any of k boxes.  Therefore, these (r-k) objects could in the k^{(r-k)} manner are organized.  Consequently, both possible ways to do this are

=\binom{r}{k} \times k! \times k^{r-k}\\\\=\frac{r! \times k^{r-k}}{(r-k)!}

Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one

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5 0
3 years ago
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<span>3 = log(8) + log(x³) </span>

<span>When adding logs, you are multiplying the terms altogether. </span>

<span>3 = log(8x³) </span>

<span>Then, by log_a b = n ==> aⁿ = b: </span>

<span>10³ = 8x³ [Since the base is not given, I assume that the base is 10] </span>
<span>1000 = 8x³ </span>

<span>Finally, solve for x. </span>

<span>1000/8 = x³ </span>
<span>x³ = 125 </span>
<span>x = (125)^(1/3) . . .Set both sides to the power of 1/3. </span>
<span>x = 5 </span>

<span>Hence, x = 5. </span>
3 0
2 years ago
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