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Arte-miy333 [17]
3 years ago
6

The sum of two numbers is –40. One number

Mathematics
1 answer:
sasho [114]3 years ago
3 0

Answer:

-27 + -13 = -40

Step-by-step explanation:

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What is the distance between 3, 5 and -4, 1
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Answer:

Distance = 8.06

Step-by-step explanation:

We have to use the distance formula d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2}  }.

(x_{1},y_{1}) = coordinates of the first point

(x_{2},y_{2} ) = coordinates of the second point

To solve, plug the appropriate values into the formula.

d=\sqrt{(-4-3)^{2} +(1-5)^{2} } = \sqrt{65} = 8.062257748

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The expression will be x-3.

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3 years ago
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What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

4 0
3 years ago
Read 2 more answers
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