Answer: x=3 y=2

Solve step-by-step:
Solve for the first variable (any variable) in one of the equations, then substitute the result into the other equation

6 0

3 years ago

Arthur is interested in the effects of sleep deprivation usage on number of calories consumed. He asks a group of 20 college stu

Greeley [361]

Answer:

Arthur knows that there is a difference among the groups somewhere, but he does not know where

Step-by-step explanation:

An ANOVA test is a test to find out whether the results of an experiment or a survey are significant or not. ANOVA test helps the researcher or the experimenter to decide whether they reject the null hypothesis or accept the alternate hypothesis in the experiment. In ANOVA test, the experimenter wants to find if there is a difference between them or not.

In the context, Arthur is doing a study and he wishes to find out effect of a sleep deprivation on the number of the calories that people consumed. He collects some data from his subject group from the sleep lab and after running the ANOVA test, he finds out that he can reject the null hypothesis. So on this basis, Arthur knows that there is some basic difference among the members of the group somewhere, but he does not know where actually the difference is.

3 0

3 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

3 years ago

Jason and his children went into a grocery store and will buy bananas and mangos. Each banana costs $0.90 and each mango costs $

Andrej [43]

Answer:

25 ≥ 0.90b + 2m

Step-by-step explanation:

Given:

Cost of each banana = $0.90

Cost of each mango = $2

Total amount = $25

Find:

Inequality

Computation:

Assume;

Number of banana = b

Number of mango = m

Total amount ≥ Cost of total banana + Cost of total mango

25 ≥ 0.90b + 2m

8 0

3 years ago