We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
Answer:
y = -3x + 1
Step-by-step explanation:
Perpendicular lines have opposite reciprocal slopes, so the slope will be -3.
Plug in the slope and given point into y = mx + b
y = mx + b
-5 = -3(2) + b
-5 = -6 + b
1 = b
Then, plug in the slope and y intercept into y = mx + b again:
y = -3x + 1 will be the equation of the line
Here’s the correct answer, how I got it, and something to help you for next time. I know it’s a lot of words but if u read the explanation it might help you :)
Answer:
Step-by-step explanation:
8/24 are Red
Pick and return 2
So it will be 7/25
Again pick and return 2
Then it is 6/26
Now multiply the results
8/24 × 7/25 × 6/26 = 7/ 325
