If Oscar the ostrich travels 126 miles in 3 hours on land, how fast does he travel?

Mathematics

1 answer:

Furkat [3]3 years ago

8 0

Answer:

If Oscar the ostrich travels 126 miles in 3 hours . that means he travels 42 miles in 1 hour. so 42mph

You might be interested in

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

12x-5y=20 y=x+4<br> 3x+y=3 x=-y+3

Vladimir79 [104]

Standard form (which I assume is what they want you to turn these into) is y=mx+b.

12x-5y=20 is y=2.4x-4.
Subtract 12x from both sides, -5y=-12x+20.
Multiply both sides by -1, 5y=12x-20.
Divide both sides by 5, y=2.4x-4.

y=x+4 is already in standard form- I'm not quite sure what to do.

3x+y=3 is y=-3x+3.
Subtract 3x from both sides, y=-3x+3.

x=-y+3 is y=-x+3
Ad y to both sides, y+x=3.
Subtract x from both sides, y=-x+3.

4 0

3 years ago

5. What are 3 true statements you can claim based on

Makovka662 [10]

Answer: 1 hour is equal to 46 miles 2 hours is 92 miles and 20 hours is 920 miles

Step-by-step explanation:

92/2 = 46 miles

46 x 2 = 92 miles

46 x 20 = 920

7 0

3 years ago

What is the center and radius of the circle with equation (x − 5)2 + (y + 6)2 = 9?