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3 years ago

If Oscar the ostrich travels 126 miles in 3 hours on land, how fast does he travel?

Mathematics

1 answer:

Furkat [3]3 years ago

8 0

Answer:

If Oscar the ostrich travels 126 miles in 3 hours . that means he travels 42 miles in 1 hour. so 42mph

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The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

3 years ago

A farmer plans to fence a rectangular corral. The diagonal distance from one corner of the corral to the opposite corner is five

garik1379 [7]

Answer:

Length of diagonal is 7.3 yards.

Step-by-step explanation:

Given: The diagonal distance from one corner of the corral to the opposite corner is five yards longer than the width of the corral. The length of the corral is three times the width.

To find: The length of the diagonal of the corral.

Solution: Let the width of the rectangular garden be x yards.

So, the length of the diagonal is $x+5$

width of the rectangular corral is $3x$

We know that the square of the diagonal is sum of the squares of the length and width.

So,

$(3x)^{2} +x^{2} =(x+5)^{2}$

$9x^{2} +x^{2} =x^{2}+10x+25$

$9x^{2}-10x-25=0$

$x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a}$

$x=\frac{10\pm\sqrt{(-10)^{2} -4(9)(-25)} }{2(9)}$

$x=\frac{10\pm\sqrt{100}}{18}$

Since, side can't be negative.

$x=\frac{5}{9}+\frac{5}{9}\sqrt{10}$

Now, length of the diagonal is

$5+\frac{5}{9}+\frac{5}{9}\sqrt{10}$

Hence, length of diagonal is 7.3 yards.

4 0

4 years ago

Can i plz have some help

daser333 [38]

Theoretical Probability is what you think the result will be, and experimental probability is what it turns out to be, hope this helps.

5 0

4 years ago

The figure below shows a rectangular window

Alexxx [7]

Where is the figureeeee??

5 0

3 years ago

Determine if triangle DEF with coordinates D (3, 2), E (4, 6), and F (7, 3) is an equilateral triangle. Use evidence to support

Anna [14]

Use the formula d=sqrt[(x₂-x₁)^2+(y₂-y₁)^2] to find distance between 2 points.
DE = √17
EF = √18
FD = √17
See the attachment for the complete workout.
Since,All the sides are not same to make an equilateral triangle.
So its not an equilateral triangle

6 0

3 years ago