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Gnoma [55]
3 years ago
15

What is the rule of this problem: 1.75,__,6.75,9.25, 11.75? Help please

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
The blank space is 4.25
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Each students in class 38 students was asked to report how many siblings he has. Data a 0/38 Data b 1/38 Data c 13/38 Data 8/38
Nezavi [6.7K]

Answer:

8/38

Step-by-step explanation:

You got it right, trust yourself

4 0
3 years ago
The age of a boy is twice that of his sister. five years ago the boy was 3 times the age of his sister. How old is the boy
joja [24]

<em>Answer</em><em>:</em>

<h2><em>2</em><em>0</em><em> </em><em>years</em><em> </em><em>old</em><em>.</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>sister</em><em> </em><em>be</em><em> </em><em>X</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>boy</em><em> </em><em>be </em><em>2</em><em>x</em>

<em>Now</em><em>,</em>

<em>Five</em><em> </em><em>years</em><em> </em><em>ago</em><em>,</em>

<em>3(x - 5) = 2x - 5 \\ or \: 3x - 15 = 2x - 5 \\ or \: 3x - 2x =  - 5 + 15 \\ x = 10</em>

<em>Again</em><em>,</em>

<em>Repla</em><em>cing</em><em> </em><em>value</em><em>,</em>

<em>age \: of \: boy = 2x \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2 \times 10 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 20</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

7 0
3 years ago
I need help fast
Pie
YZ since they are in the same spot in the cong statement
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After spraying perfume on her neck, Tasha becomes less aware of the scent over time. What property is this describing
Yuri [45]

Answer:

Sensory adaptation? im guessing

Step-by-step explanation:

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P = 240 – 172<br>g=<br>9 x 8/-24<br><br>Work out the value of p×q​
mel-nik [20]

Step-by-step explanation:

I hope I got it right and I hope this helps

7 0
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