The position function of a particle is given by:

The velocity function is the derivative of the position:

The particle will be at rest when the velocity is 0, thus we solve the equation:

The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
![t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting:
![\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81-4%282%29%28-18%29%7D%7D%7B2%282%29%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81%2B144%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B225%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm15%7D%7B4%7D%20%5Cend%7Bgathered%7D)
We have two possible answers:

We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
Answer: option 1.
Explanation:
feasible region is that region which is formed by the lines of constraints.
feasible region is shaded in the attached graph
inequalities becomes equalities to draw the graph
and lines will head towards the origin if constraint satisfied by putting x= 0, y=0
and on the contrary lines will move away from origin when condition of constraint does not satisfied.
Answer:
The question is asking which numbers are larger with respect to one another. An easy way to do this is to convert to decimals, or just memorize it. 1/2=0.5, 3/4=0.75, 2/3=0.666666. So descending order (largest to smallest) 3/4, 2/3, 1/2.
128.34
= 128+ 0.34
= 128+ 34/100
= 128+ (34/2) / (100/2)
= 128+ 17/50
= 128 17/50
128.34 written as a mixed number is 128 17/50~