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Zigmanuir [339]
3 years ago
9

PLEASE HELP!!! In the diagram, line AB is a perpendicular bisector of segment CD. What is the length of CD?

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

12

Step-by-step explanation:

AD is 6. a bisector splits a line in half. X would equal 6 meaning AD would equal 12.

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What is the oblique asymptote of the function f(x) x^2+x-2/x+1
Mamont248 [21]
f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}


\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0

Consequently, t<span>he limit of f(x) as x approaches infinity is x.

In other words, f(x) approaches the line y=x, 
</span><span>
so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.</span>

3 0
3 years ago
Sue chooses a dress to wear when she goes out with her parents, but she can wear it only if her parents approve. The probability
Sophie [7]
12%

40% = 0.4
30 = 0.3

0.3 x 0.4 = 0.12

0.12 = 12%

4 0
3 years ago
For a horizontal launch (θ0 = 0) at a fixed height ℎi &gt; 0, are the statements below correct? (Assuming friction can be ignore
Marizza181 [45]

Answer:

1) False. 2) True. 3) True. 4) False.

Step-by-step explanation:

1) False. The force of gravity will drive it down. The path will form a parabola.

2) True. There is no variation in the velocity in the horizontal axis and no force applied so the acceleration is zero.

3) True. The travel time depends on the height and the acceleration of gravity, and independent of the velocity of the rocket at launch.

4) False. The travel distance depends on the initial velocity of the rocket (at launch).

5 0
3 years ago
What is the rate of change for f(x) =7 sin x-1 on the interval from x=0 to x=piover 2
Oksi-84 [34.3K]
\bf slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby &#10;\begin{array}{llll}&#10;average\ rate\\&#10;of\ change&#10;\end{array}\\\\&#10;-------------------------------

\bf f(x)= 7sin(x)-1  \qquad &#10;\begin{cases}&#10;x_1=0\\&#10;x_2=\frac{\pi }{2}&#10;\end{cases}\implies \cfrac{f\left( \frac{\pi }{2} \right)-f(0)}{\frac{\pi }{2}-0}&#10;\\\\\\&#10;\cfrac{[7\cdot 1-1]~-~[7\cdot 0-1]}{\frac{\pi }{2}}\implies \cfrac{6-(-1)}{\frac{\pi }{2}}\implies \cfrac{6+1}{\frac{\pi }{2}}\implies \cfrac{7}{\frac{\pi }{2}}\implies \cfrac{14}{\pi }
7 0
3 years ago
Suppose a2 + 4a + 3 represents the area of a rectangle. What is the perimeter of that rectangle? A) 2a + 4 B) 4a + 8 C) 6a + 12
allsm [11]
A² + 4a + 3
(a+3)(a+1)         This is the length and the width of the rectangle.

Perimeter = length + length + width + width
P = (a+3) + (a+3) + (a+1) + (a+1)
P = a + a + a + a + 3 + 3 + 1 + 1
P = 4a + 6 + 2
P = 4a + 8

B) 4a + 8 
5 0
3 years ago
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