Answer:
a.
<u>Increasing:</u>
x < 0
x > 2
<u>Decreasing:</u>
0 < x < 2
b.
-1 < x < 2
x > 2
c.
x < -1
Step-by-step explanation:
a.
Function is increasing when it is going up as we go rightward
Function is decreasing when it is going down as we go rightward
We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).
So,
<u>Increasing:</u>
x < 0
x > 2
The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:
<u>Decreasing:</u>
0 < x < 2
b.
When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].
Looking at the graph, it is
from -1 to 2 (x axis)
and 2 to positive infinity
We can write:
-1 < x < 2
x > 2
c.
Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.
This will be the other intervals than the ones we mentioned above in part (b).
Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:
x < -1
Answer:
(x-7) (x+4)
Step-by-step explanation:
x^2 - 3x - 28
What two numbers multiply to -28 and add to -3
-7*4 = -28
-7+4 = -3
(x-7) (x+4)
Answer: FIRST OPTION.
Step-by-step explanation:
Regular polygons are those polygons whose sides are equal in length and whose angles are all equal.
By definition each interior angle of a Regular polygon,is:
(In degrees)
Where "n" is the number of sides of the polygon.
Observe the Regular polygon given in the exercise.
Since it has 6 sides, you can conclude that it is an Hexagon. Then:
Substituting into and evaluating, you get:
Knowing this, you can write the following equation:
Finally, you must solve for "x" in order to find its value. This is:
Answer:
First tangent line:
Second tangent line:
Notice: slope of -1 means that both 
are equal to -1, so 
You had the right idea using the Pythagorean theorem to solve for b.
Problem is for that triangle to work, the 5 and the 2√2 would have to switch places. The length of a leg cannot be larger than the length of the hypotenuse for it to truly be a right triangle.
Pythagorean theorem only works for the right triangles. Only way to "solve this problem would be to bring in complex numbers.
5² + b² = (2√2)²
25 + b² = 2²(√2)²
25 + b² = 4(2)
25 + b² = 8
b² = 8 - 25
b² = - 17
b = √-17
b= (√17i)
Then the problem with THIS is a measurement/distance cannot be negative... which goes against exactly what that complex number i is.
