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Anna35 [415]
3 years ago
14

Find all real zeros of the function y=-5x-7

Mathematics
2 answers:
Yakvenalex [24]3 years ago
5 0

Answer:

x=1 2/5

Step-by-step explanation:

Replace y with 0 and solve for x.

Ahat [919]3 years ago
4 0

Answer:  The required zero of the given function is x = -1.4.

Step-by-step explanation:  We are given to find all the real zeroes of the following function :

y=-5x-7~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the given function is linear, so it will have only one real zero.

Also, the zeroes of a function y = f(x) is given by f(x) = 0.

So, the zero of the given function (i) is

y=0\\\\\Rightarrow -5x-7=0\\\\\Rightarrow 5x=-7\\\\\Rightarrow x=-\dfrac{7}{5}\\\\\Rightarrow x=-1.4.

Thus, the required zero of the given function is x = -1.4.

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All numbers streets runs parallel to each other both 3rd and 4 the streets are intersected by king Ave
erastova [34]

Answer:

Step-by-step explanation:

King avenue becomes the base

He turns left into the side meet right angle side.

Therefore the hypotenuse cuts through the houses and becomes a measure

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Hypotenuse + 7000mB = 3rd St 5000m A.

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3 years ago
Help!! Answer !!! about to run out of time in test!!
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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

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