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Oduvanchick [21]
3 years ago
6

What is the equation in standard form of the

Mathematics
1 answer:
galben [10]3 years ago
4 0

Answer:yes that’s how you do it you need to do pemdas snd then you use frsctions

Step-by-step explanation:

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Martha is making a scarf for her sister each day she knits 1/6 of a scarf what fraction of the scarf will be complete after thre
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Multiply 1/6 by 3 =1/2
In 3 days she would have completed 1/2 of the scarf.
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3 years ago
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A quiz in statistics course has four multiple-choice questions, each with five possible answers. A passing grade is three or mor
nekit [7.7K]

Answer:

a) 0.0016

b) 0.0224

Step-by-step explanation:

If every question has 5 possible answers, the probability of getting the correct answer by guessing would be 0.20. The probability of getting an incorrect answer would be 0.80.

a)Find the probability she lucks out and answers all four questions correctly.

To do this, Allison would have to guess right the first, second, third AND fourth answers. Therefore, we have to multiply the probabilities:

0.20 x 0.20 x 0.20 x 0.20 = 0.0016

The probability that she answers all 4 questions correctly is 0.0016.

b) Find the probability that she passes the quiz.

To pass the quiz, she has to have three OR 4 correct answers:

  1. The probability that she has 3 correct answers is: 0.20 x 0.20 x 0.20 x 0.80 (since she has to have 1 correct answer and 1 incorrect one) = .0064.
  2. We already calculated the probability that she guesses 4 answers correctly: 0.0016.

Now, we have to sum up these two scenarios:

0.0064 + 0.016 = 0.0224.

Thus, the probability that she passes the quiz is 0.0224

3 0
3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
I need help with this question!!!
CaHeK987 [17]

K is equal to 2.

You have to move the 4 to the other side and change the addition sign to subtraction. After that, you have to subtract 8 and 4 which will give you 4 and 4 divided by 2 is 2 which means that k equals 2.

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3 years ago
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Juan bought a piece of lumberthat is 20 feet long.
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