You're right, its B. I just took the test and got a 100%. Good luck on your test.
X= 27
Because
3x−4y=65
(3x−4y)+4y=65+4y
3x−4y+4y=4y+65
3x=4y+65
Let X be the number of defective transistors. Let p be the probability that defective transistor.
P(defective transistor) = 0.04
P(non defective ) = 1- 0.04 = 0.96
A random sample of size 30 is tested for defects and we want to find probability of no defective transistor
P(No defective transistor) = P(X= 0)
Here X follows binomial distribution with parameters n=30 and p=0.04
The Binomial probability function with parameters n and p is
P(X=x) =
P(X=0) =
Using n=30 and p=0.04
P(X=0) =
P(X=0) = 1*1*(0.96)^30
P(X=0) = 0.2938
The probability that there are no defective transistors in the sample is 0.2938
Answer:
The answer is 5.
Step-by-step explanation:
-3-(-8) = -3+8 = 5.
Answer:
See explanation
Step-by-step explanation:
The constant of variation is found using the slope formula:
The given relation is
X : -2 , -3, -4, -5
Y : -5, -7.5,-10,-12.5
We can use any two ordered pair to find the constant of variation.
Using (-2,-5) and (-3,-7.5), we have
The constant of variation is 2.5
We need to repeat this for all the options to identify the one with -2.5 as slope.
unfortunately, you did not provide the remaining options.