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Given :
A sailor is 30 m above the water in the crow's nest on a sailboat.
The sailor encounters an orca surface at an angle of depression of 15 degrees.
The crows nest is 20 m horizontally from the bow (front) of the boat.
To Find :
How far in front of the boat is the orca.
Solution :
Let, distance of boat front from the crow's nest is x.
So,
Hence, this is the required solution.
Answer:
6 runners finished the race
Step-by-step explanation:
it starts with 90 runners. then 1/3 of them dropped out in the second half of the race, that means you do 90 divided by 3
90 ÷ 3 = 30
Then, 1/5 of the runners remained.
That means you do 30 divided by 5
30÷ 5= 6
so the answer is 6 remaining runners finished the race.
Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
The dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∴ ∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∴ ∠x + 90° = 180°
Hence;
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
∴ 90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
