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2 years ago

10

Multiply.

1 answer:

3241004551 [841]2 years ago

6 0

Answer:

Ans; 58.80528

Step-by-step explanation:

Ans; ( 8.73) ( 42.1)(0.16) = (873) ( 421) (16) × 10^-⁵ = ( 367533) (16) × 10^-⁵ = 5880528 × 10^-⁵ = 58.80528

I hope I helped you^_^

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What is the total cost of a pair of jeans that are priced $40.00 if there is a 6.5% sales tax? $40.65 $42.60 $44.00 $46.50

-Dominant- [34]

A pair of jeans = $40.00
There is a 6.5% sales tax.

First change the % into a decimal by moving the decimal point two spaces to the left.
0.065

Multiply that by 40.00 to find out how much the tax is.

40 × 0.065 = 2.6

Now add the tax to the initial price.
40.00 + 2.6 = 42.60

The total cost is $42.60.

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2 years ago

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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2 years ago

What plus 4/3 equals 19/3 in the simplest form?

dangina [55]

15/3 + 4/3 = 19/3

All you have to do is subtract 4/3 from 19/3 to get 15/3

4 0

2 years ago

A student takes a driving test until it is passed.

Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

+ P (Passing in the 4th attempt)

+ P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then, P (Passing in the 2nd attempt) = $(\frac{3}{7}) \times (\frac{4}{7})$

Similarly, P (Passing in the 4th attempt) = $(\frac{3}{7})^{3} \times (\frac{4}{7})$ , since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = $(\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...$

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

$S=\frac{a}{1-r^{2}}$

The probability is:

P (even number of tests) = $(\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...$

$=\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\ =\frac{12}{40}\\ =0.30$

Thus, the probability that the test is taken an even number of times is 0.30.

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3 years ago

Had 24 beads he divided them into four equal groups and gave one group to his sister how many beads did Lawrence have then

const2013 [10]

Answer:

If Lawrence has 24 beads and divided them into 4 groups you want to see how many he put into each group first

To do this we are going to take 24/4=6

Each group has 6 in it

If he gave one group to his sister, than he gave 6 beads to his sister

Now we want to take 6 away from 24 to find out how many he has left

24-6=18

He now has 18 beads

Hope this helps ;)

3 0

3 years ago

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