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Oksi-84 [34.3K]
3 years ago
15

1 divided by 1/10... ya thats about it...​

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

10

Step-by-step explanation:

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Multi step equations 4x+6+3=17
Kobotan [32]
First, you add like terms.  In this case, the like terms are 6 and 3.

4x + 6 + 3 = 17
4x + 9 = 17

Then, subtract 9 on each side:

4x + 9 - 9 = 17 - 9
4x = 8

Then divide by 4 on each side to get the x by itself:

4x/4 = 8/4
x = 2
8 0
3 years ago
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Solve this equation! Please Help!<br><br> √3 x 66.15/4.41<br><br> (SHOW YOUR WORK)
finlep [7]
Hi Jessica,
<span>Remember PEMDAS (Parenthesis, Exponents, Multiplication & Division, Addition & Subtraction).

√3 x 66.15/4.41 {Exponents/Cube & Square Roots First}

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7 0
3 years ago
The number of kilograms of water in a human body varies directly as the mass of the body. An 87​-kg person contains 58 kg of wat
katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form y=kx, where y varies directly with x and k is constant of variation.

We are told that an 87​-kg person contains 58 kg of water. We can represent this information in an equation as:

58=k\cdot 87

Let us find the constant of variation as:

\frac{58}{87}=\frac{k\cdot 87}{87}

\frac{29*2}{29*3}=k

\frac{2}{3}=k

The equation y=\frac{2}{3}x represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute x=75 in our given equation and solve for y.

y=\frac{2}{3}(75)

y=2(25)

y=50

Therefore, there are 50 kg of water in a 75​-kg person.

3 0
3 years ago
(A) {(-6,2), (3, 4), (4,4), (5, 6)}<br> DOMAIN:<br> RANGE:<br> Is the relation above a function?
vovikov84 [41]

Answer:

Yes

Step-by-step explanation:

Domain: {-6, 3, 4, 5}

Range: {2, 4, 6}

This relation is a function.

6 0
2 years ago
Given that ∠S ≅ ∠A, and AB ≅ ST , what is the third congruence needed to prove that ΔABC ≅ ΔSTU by ASA?
Olenka [21]

Answer:

angle-side-angle. that's my answer

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