Solution:
<u>Note that:</u>
- Speed = Distance/Time
- Vaimiti speed = 1.1 m/s
- Jabril speed = 1.3 m/s
<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>
- Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
- => Vaimiti's time to reach school: 1500 seconds
<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>
- Jabril's time to reach school: 30 minutes = 30 x 60 seconds
- => Jabril's time to reach school: 1800 seconds
<u>Finding the distance of Vaimiti:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- => 1.1 meters/second = Distance/1500
- => 1.1 x 1500 = Distance
- => 1650 meters = Distance (In meters)
<u>Finding the distance of Jabril:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- 1.3 meters/second = Distance (In meters)/1800 seconds
- => 1.3 x 1800 = Distance (In meters)
- => 2340 meters = Distance (In meters)
This can lead to two possible solutions:
Possible solution #1:
<u>Finding the difference between the two distances:</u>
- 2340 meters - 1650 meters = Difference (In meters)
- => 690 meters
Possible solution #2:
The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.
Hoped this helped!
Answer:
87 + 8r
Step-by-step explanation:
We have a variable that we cannot simplify further:
8r
But we have two numbers that we can simplify:
94 - 7 = 87
Then we add those together:
8r+87
y=2/3y-3
1. y = 2/3 (9)-3 multiply 9 and 2 =18/3
y=18/3-3 divide 18 and 3 =6
y=6-3 subt. 3
y=3
2. -11=2/3x - 3
-11+3 = 2/3 x add 3 to both sides to cancel -3
-8=2/3 x
(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3
-24/2 = x divide
-12=x
Answer:
C
Step-by-step explanation:
Multiply the top and bottom, both by sqrtx-sqrt5. This is in order to rationalize the denominators.
You get answer C.
Answer:
455ways
Step-by-step explanation:
This is expressed as 15 C 3 ( C- combination)
The concept of combination is used when we talk about selection.
Now we are selecting 3 from a sample of 15
15 C 3 = 15! / (15-3)! 3! = 15 ×14×13×12!/12!×3×2
= 5 × 7 × 13 = 455ways
