I need help quick please

PtichkaEL [24]

It's two. 50% chance of heads, 50% chance of tails.

7 0

2 years ago

FLVS STUDENTS !!! For the 5.05 Two-Variable Linear Inequalities algebra 1 assignment can someone send me there answers ?!?!?!

iogann1982 [59]

Degree is the value of the highest power of the variable, and hence in this case is 8

6 0

3 years ago

A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that

mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = probability of obtaining head.

So, Null Hypothesis, $H_0$ : p = 0.5

Alternate Hypothesis, $H_A$ : p $\neq$ 0.5

(a) The significance level of the test which is represented by $\alpha$ is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

P(Type I error) = $\alpha$

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

$\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0} +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}$ = $\alpha$

$(1\times 1\times 0.5^{10}) +(1 \times 0.5^{10} \times 0.5^{0})$ = $\alpha$

$\alpha$ = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - $\beta$ ).

So, here, X ~ Binom(n = 10, p = 0.1)

$1-\beta$ = P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true)

$1-\beta$ = $\binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0} +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}$

$1-\beta$ = $(1\times 1\times 0.9^{10}) +(1 \times 0.1^{10} \times 0.9^{0})$

$1-\beta$ = 0.3487

Hence, the power of the test is 0.3487.

3 0

3 years ago

6x - 2(x + 2) > 2 - 3(x+3) Solve the inequality plz help

Mumz [18]

Answer:

x > -3/7

Step-by-step explanation:

6x - 2(x + 2) > 2 - 3(x + 3)

Distribute the two and three inside the parenthesis.

6x - 2x - 4 > 2 - 3x - 9

Combine like terms.

4x - 4 > -3x - 7

Add 4 to both sides.

4x > -3x - 3

Add 3x to both sides.

7x > -3

Divide both sides by 7.

x > -3/7

7 0

3 years ago

Read 3 more answers

This quiz it is rlly hard

lawyer [7]

Answer:

396cm I think.

Step-by-step explanation:

10 x (27 - 8) + 9 x 24

4 0

2 years ago