Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• 1 + cot² x = csc²x and csc x = ![\frac{1}{sinx}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bsinx%7D)
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
sin²Θ( 1 + cot²Θ )
= sin²Θ × csc²Θ
= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified
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Consider the left side
cos²Θ - sin²Θ
= cos²Θ - (1 - cos²Θ)
= cos²Θ - 1 + cos²Θ
= 2cos²Θ - 1 = right side ⇒ verified
Answer:
negative pie/10 radians
Step-by-step explanation:
d on edg
Answer:
![x = \{13,14\}](https://tex.z-dn.net/?f=x%20%3D%20%5C%7B13%2C14%5C%7D)
Step-by-step explanation:
Given
![x + 2x + 6 < 50](https://tex.z-dn.net/?f=x%20%2B%202x%20%2B%206%20%3C%2050)
Required
True values of x
We have:
![x + 2x + 6 < 50\\](https://tex.z-dn.net/?f=x%20%2B%202x%20%2B%206%20%3C%2050%5C%5C)
![3x + 6 < 50](https://tex.z-dn.net/?f=3x%20%2B%206%20%3C%2050)
Collect like terms
![3x < 50-6](https://tex.z-dn.net/?f=3x%20%3C%2050-6)
![3x < 44](https://tex.z-dn.net/?f=3x%20%3C%2044)
Divide both sides by 3
![x < 44/3](https://tex.z-dn.net/?f=x%20%3C%2044%2F3)
![x < 14.67](https://tex.z-dn.net/?f=x%20%3C%2014.67)
This means that x has a value lesser than 14.67.
Hence, the valid values are:
![x = \{13,14\}](https://tex.z-dn.net/?f=x%20%3D%20%5C%7B13%2C14%5C%7D)
Answer:
you still need help ?
Step-by-step explanation:
Answer:
what
Step-by-step explanation: