Question

REEEEEEEE ID LOVE SOME HELP!! <3333 8v^2+37v=0 (solve) solve a quadratic equation (topic)

Answer 1

Answer:

Solving the quadratic equation $8v^2+37v=0$ we get: $\mathbf{v=0\:or\:v=\frac{-37}{8}}$

Step-by-step explanation:

We need to solve the quadratic equation: $8v^2+37v=0$

We can solve the quadratic equation of form $ax^2+bx+c=0$ using quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We need to put values of a , b and c in order to find the solutions of quadratic equations.

In the given equation: $8v^2+37v=0$ we have, a =8, b=37, c=0

Putting values and finding the values for n:

$v=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\v=\frac{-37\pm\sqrt{(-37)^2-4(8)(0)}}{2(8)}\\v=\frac{-37\pm\sqrt{(-37)^2-0}}{2(8)}\\v=\frac{-37\pm\sqrt{1369}}{2(8)}\\v=\frac{-37\pm37}{2(8)}\\v=\frac{-37+37}{2(8)}\:or\:v=\frac{-37-37}{2(8)}\\v=\frac{0}{2(8)}\:or\:v=\frac{-74}{2(8)}\\v=0\:or\:v=\frac{-37}{8}$

So, solving the quadratic equation $8v^2+37v=0$ we get: $\mathbf{v=0\:or\:v=\frac{-37}{8}}$