Step 1: Subtract -2 from both sides.<span><span><span><span>
m2</span>+<span>4m</span></span>−<span>(<span>−2</span>)</span></span>=<span><span>−2</span>−<span>(<span>−2</span>)</span></span></span><span><span><span><span>
m2</span>+<span>4m</span></span>+2</span>=0</span>
Step 2: Use quadratic formula with a=1, b=4, c=2.<span>
m=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>
m=<span><span><span>−<span>(4)</span></span>±<span>√<span><span><span>(4)</span>2</span>−<span><span>4<span>(1)</span></span><span>(2)</span></span></span></span></span><span>2<span>(1)</span></span></span></span><span>
m=<span><span><span>−4</span>±<span>√8</span></span>2</span></span><span><span>
m=<span><span>−2</span>+<span><span><span>√2</span><span> or </span></span>m</span></span></span>=<span><span>−2</span>−<span>√2</span></span></span><span>
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32 but make sure it’s emedicpend PAS
A] <span>A remote-control airplane descends at a rate of 2 feet per second. After 3 seconds it is 67 feet above the ground.
the point slope equation will be given as follows:
y-y1=m(x-x1)
where:
slope,m=2 ft/sec
(x1,y1)=(3,67)
thus plugging in the values in the formula, we obtain the point slope equation as follow:
y-67=2(x-3)
Answer:
</span>y-67=2(x-3)
b]The height of the plane after 8 seconds will be:
x=8 sec
but:
y-67=2(x-3)
substituting x=8 we get:
y-67=2(8-3)
y-67=2(5)
y=10+67
y=77
thus the height after 8 seconds is 77 ft