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3 years ago

Help please! Thank you! :D❤️

Mathematics

1 answer:

MissTica3 years ago

7 0

I believe it is GCF because 9v^3 can be factored out of the expression, becoming:
9v^3 (4 - 3v^2)
9v^3 (-3v^2 + 4)
The quadratic in parentheses can be solved, but with the quadratic equation or by graphing.

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Help anyone? please?

ValentinkaMS [17]

Answer:

x=11.2

Step-by-step explanation:

Set up a proportion:

x+11/36 = 37/60

Cross multiply:

1332=60(x+11)

Distribute:

1332=60x+660

Subtract 660 from 1332

672=60x

Divide:

x=11.2

I'm not sure if this is the correct answer but I hope this helps! :)

Correct me if I'm wrong!

6 0

3 years ago

For the given central angle, determine the distance traveled along the unit circle from the point (1,0). 57

aliina [53]

Answer: (a)- $0.99\ \text{units}$

Step-by-step explanation:

Given

Central angle is $57^{\circ}$

The radius of the unit circle is $1\ \text{unit}$

Arc length is given by

$\Rightarrow l=\dfrac{\theta}{360^{\circ}}\times 2\pi r$

Put the values

$\Rightarrow l=\dfrac{57}{360}\times 2\pi \cdot1\\\\\Rightarrow l=0.99\ \text{units}$

6 0

3 years ago

Solve.<br> (2x+24)(4x+36)

Eva8 [605]

You just need to foil. 2x times 4x times 2x times 36 times 24 times 4x times 24times 36. then solve.

7 0

3 years ago

Read 2 more answers

Only using 2,3,5,8 once to get 104 as many times as possible

Arte-miy333 [17]

8x(5x2+3)=8x(15+3)=8x13=104

3 0

3 years ago

Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals

trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

The surface is given by the equation

f(x,y,z) = 0 where

$f(x,y,z)=-2x^2+2y^2-3z^2+3$

The gradient of this function is the vector

$(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)$

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

The vectors with their tails at P are of the form

(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)

as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

$(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3$

and the equation of the desired plane is

4x+4y+3z = -3

3 0

3 years ago