Answer:
Step-by-step explanation:
The graph shows the solution (-6,2)
i.e at x= -6 y=2
Analysis of each of the answers, since we can't write the equation of a straight line with only that information i.e the single point
Then,
Option 1
1. 2x - 3y = -6
x= -6 y=2
Then let insert x=-6 and y =2
2(-6)-3(2)
-12-6
-18.
Since -18 ≠ -6, then this is not the equation of the line and doesn't make up the system
Option 2
2. 4x - y = 26
Inserting x=-6 and y=2
4(-6)-(2)
-24-2
-26
Since -26 ≠ 26, then this is not the equation of the line and doesn't make up the system
Option 3
3. 3x + 2y = -14
Inserting x=-6 and y=2
3(-6)+2(2)
-18+4
-14
Since -14 ≠ -14 then this is the equation of the line and it make up the system.
Option 4
x-y = -2
Inserting x=-6 and y=2
(-6)-(2)
-6-2
-8
Since -8≠ -2, then this is not the equation of the line and doesn't make up the system
Option 5
5. x+y=-4
Inserting x=-6 and y=2
(-6)+(2)
-6+2
-4
Since -4 ≠ -4, then this is the equation of the line and it makes up the system.
Then, there are two option that make up the system
3. 3x + 2y = -14
And
5. x+y=-4
Answer:

Step-by-step explanation:
*Move terms to the left and set equal to zero:
4㏒(√x) - ㏒(3x) - ㏒(x²) = 0
*simplify each term:
㏒(x²) - ㏒(3x) - ㏒(x²)
㏒(x²÷x²) -㏒(3x)
㏒(x²÷x² / 3x)
*cancel common factor x²:
㏒(
)
*rewrite to solve for x :
10⁰ = 
1 = 
1 · x =
· x
1x = 
*that would be our answer, however, the convention is to exclude the "1" in front of variables so we are left with:
x = 
Answer:
QR and CD
Step-by-step explanation:
TQRS is similar to BCDE. Align the letters.
T Q R S
B C D E
Some examples of corresponding sides.
TS and BE
TQ and BC
Answer:
<h2>If A= 3 And Given Equation is </h2><h2>B = 2 3B - 2 (1-B) ÷ A-2 </h2><h2> Here is solution ⤵️⤵️</h2>
Step-by-step explanation:
<h3>4.666667</h3>
Answer:
The measures of the intercepts arcs are
and 
Step-by-step explanation:
we know that
The measurement of the outer angle is the semi-difference of the arcs which comprises
Let
x,y -----> the intercepts arcs
----> equation A


------> equation B
substitute equation B in equation A




Find the value of x

therefore
The measures of the intercepts arcs are
and 