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xeze [42]
3 years ago
13

Find a ratio that compares the relative sizes of the quantities. 46 to 23

Mathematics
1 answer:
Zanzabum3 years ago
7 0
\frac{46}{23}=\frac{2 \times 23}{1 \times 23}=\frac{2}{1}

The ratio is 2:1.
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--------------------------------------------------------------------------
Equation
-------------------------------------------------------------------------- 
 y - 9  = -  \dfrac{1}{2} (x + 2)

--------------------------------------------------------------------------  
Rearrange the equation
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y - 9 = - \dfrac{1}{2} (x + 2) \\ \\
 y - 9 = - \dfrac{1}{2}x - 1 \\ \\
 y - 9 + 9 = - \dfrac{1}{2}x - 1  + 9 \ \Longleftarrow \text{add 9 to both side} \\ \\
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slope of the perpendicular line
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slope = 2

(*the slope of the perpendicular line is the <span>negative reciprocal of the slope of line)</span>

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Substitute slope into equation y = mx + c
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y = 2x + c

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Find y-intercept
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y = 2x + c
At point (0, 4)
4 = 2(0) + c
c = 4

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Substitute y-intercept into the equation y = 2x + c
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y = 2x + 4

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Answer: y = 2x + 4
----------------------------------------------------------------------------- 

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