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3 years ago

What is the area of this parralelogram? h=4 inch b=7 inch

Mathematics

2 answers:

cestrela7 [59]3 years ago

4 0

Answer:

28cm^2

Step-by-step explanation:

4 x 7

kozerog [31]3 years ago

4 0

Answer:

no sé nada de inglés we ya me entiendes si supiera te ayudará pero eso está difícil busca por internet

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A rectangular prism has a length of 13 meters, a height of 8 meters, and a width of 9 meters. What is its volume, in cubic meter

Angelina_Jolie [31]

Answer:

V =936 m^3

Step-by-step explanation:

The volume of a cube is given by

V = l*w*h

V = 13*8*9

V =936 m^3

4 0

3 years ago

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HELP! USE EITHER LAW OF SINE OR LAW OF COSINE! HELP PLEASE! FIND THE MISSING SIDE AND MISSING ANGLES!

Eva8 [605]

Answer:

∠Q ≈ 42.969, ∠P ≈ 52.03, QR ≈ 15.036

Step-by-step explanation:

Law of sines:

13/sin Q = 19/sin 85°

=> sin Q = 13 × sin 85°/19

=> Q = sin^-1 (13 × sin 85°/19)

=> Q ≈ 42.969

∠P=> 180 - 85 - 42.969 ≈ 52.03

QR/sin 52.03° = 19/sin 85°

=> QR = sin 52.03° × 19/sin 85°

=> QR ≈ 15.036

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3 years ago

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Lina20 [59]

Step-by-step explanation:

mình nghĩ là như vầy. Chúc bạn học tôt :))))

8 0

3 years ago

Consider the system of linear equations y=3x+5 y=Mx+b Which values an M & B will create a system of linear equations with no

OLEGan [10]

Answer:

value of 'm' equal to 5 will produce no solution as they'll be parallel lines

value of 'b' equal to 5 will produce no solution because it will be the same line

Step-by-step explanation:

5 0

3 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two

wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean = $\lambda=2$ errors per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

Now, the probability that a randomly selected page does not need to be retyped is given by :-

$P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767$

Hence, the required probability :- 0.6767

6 0

3 years ago