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jeka94
3 years ago
13

What is the area of this parralelogram? h=4 inch b=7 inch

Mathematics
2 answers:
cestrela7 [59]3 years ago
4 0

Answer:

28cm^2

Step-by-step explanation:

4 x 7

kozerog [31]3 years ago
4 0

Answer:

no sé nada de inglés we ya me entiendes si supiera te ayudará pero eso está difícil busca por internet

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Montano1993 [528]

Answer:

yes my answer is yes kind sir

7 0
3 years ago
Y=2x+4 I need what the graph would look like. Please help me!
Veseljchak [2.6K]

Answer: I attached a picture of the graph

6 0
2 years ago
Read 2 more answers
A garden is in the shape of a square with a perimeter of
ElenaW [278]

The perimeter of a square is the sum of its sides and they are all equal, so to obtain the length of each of them we divide the perimeter of the first fence between 4:

 P1= 64 feet/4 sides

 P1= 16 feet

 Then, the length of each side of the second fence will increase 2 feet at each end, as shown in the figure. We have then that the perimeter of the second fence is:

 P2 = 20 feet x 4 sides

 P2 = 80 feet

 The sum of the perimeters of both fences is:

 PT = P1 + P2

 PT = 64 feet + 80 feet

 PT = 144 feet

 Total cost = 1.17 $ x 144 feet

 Total cost = 168.48 $

 The total cost of the fences was $ 168.48

6 0
3 years ago
I need help with this question asap
Nataly_w [17]

Answer:

The correct answer would be the bottom equation.

Step-by-step explanation:

y=7.25x

y=7.25(3)

y=21.75

y=7.25(4)

y=29.00

y=7.25(5)

y=36.25

7 0
3 years ago
Two pounds of grapes cost 6$ what number belongs in the most right empty cell?
sdas [7]

Answer:

Table shown below

Step-by-step explanation:

Table shown below

To solve this problem let's use proportions.

If 2 pounds of grapes cost $6, half the amount will cost half the dollars, so the last row will have $3 in the price

For the second row, we know the price is $1, that is, one-sixth of the original given price. It should correspond to one-sixth of the amount of grapes or 2/6 pounds.

Simplifying the fraction, we get 1/3 or 0.33 pounds

6 0
3 years ago
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